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photoshop1234 [79]
3 years ago
13

A machine can never be 100% efficient because some work is always lost due to which factor?

Physics
2 answers:
Pachacha [2.7K]3 years ago
8 0

Answer:

A. can never be efficient due to friction

Nataliya [291]3 years ago
5 0

HEY!!

Answer:

A. friction

Explanation:

Now if we obtain output work same as input energy then it is 100% efficient.

but this is only possible when we have no energy loss while it is not possible due to many reasons:

one of the main cause of energy loss is friction

A machine can never be 100% efficient because some work is always lost due to the lack of materials or equipment that would convert work by 100%. but so far, no machine has got 100% efficiency.

So when the machine are working there must be a friction between its working parts due to which the out-input energy is lost in different parts and hence we can never be 100% efficient machine.

HOPE IT HELPS!!

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Do this work if someone give correct answer I make her brainliest do this worksheet please
ArbitrLikvidat [17]

Sry,I only know the answer of q2

Chlorine is a non metal because it is bad conductor of heat and sodium is a metal because it is good conductor of heat.

The 3 ways in which metal is different from non metal are given below:

1)metal are good conductor of heat but nonmetal are bad conductor of heat.

2)metals are malleable but non metal aren't malleable.

3)metals are generally ductile but non metal aren't ductile.

Hope it will helpyou!

4 0
3 years ago
Read 2 more answers
The atomic mass of an element is defined as the weighted average mass of that element’s
marishachu [46]

Answer:

False

Explanation:

Atomic mass (Also called Atomic Weight, although this denomination is incorrect, since the mass is property of the body and the weight depends on the gravity) Mass of an atom corresponding to a certain chemical element). The uma (u) is usually used as a unit of measure. Where u.m.a are acronyms that mean "unit of atomic mass". This unit is also usually called Dalton (Da) in honor of the English chemist John Dalton.

It is equivalent to one twelfth of the mass of the nucleus of the most abundant isotope of carbon, carbon-12. It corresponds roughly to the mass of a proton (or a hydrogen atom). It is abbreviated as "uma", although it can also be found by its English acronym "amu" (Atomic Mass Unit). However, the recommended symbol is simply "u".

<u> The atomic masses of the chemical elements are usually calculated with the weighted average of the masses of the different isotopes of each element taking into account the relative abundance of each of them</u>, which explains the non-correspondence between the atomic mass in umas, of an element, and the number of nucleons that harbors the nucleus of its most common isotope.

4 0
4 years ago
Speed has ____ magnitude and _____ direction ??
ArbitrLikvidat [17]
Speed has only magnitude and no direction. 
6 0
3 years ago
Need help with 7 questions I'll give 26 points for the best answer!!
GaryK [48]

Room temperature

Oxygen

6 0
3 years ago
Read 2 more answers
Ocean waves pass through two small openings, 20.0 m apart, in a breakwater. You're in a boat 70.0 m from the breakwater and init
Klio2033 [76]

Answer:

λ = 5.65m

Explanation:

The Path Difference Condition is given as:

δ=(m+\frac{1}{2})\frac{lamda}{n}  ;

where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.

m = no of openings which is 2

∴δ= \frac{3*lamda}{2}

n is the index of refraction of the medium in which the wave is traveling

To find δ we have;

δ= \sqrt{70^2+(33+\frac{20}{2})^2 }-\sqrt{70^2+(33-\frac{20}{2})^2 }

δ= \sqrt{4900+(\frac{66+20}{2})^2}-\sqrt{4900+(\frac{66-20}{2})^2}

δ= \sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }

δ= \sqrt{4900+43^2}-\sqrt{4900+23^2}

δ= \sqrt{4900+1849}-\sqrt{4900+529}

δ= \sqrt{6749}-\sqrt{5429}

δ=  82.15 -73.68

δ= 8.47

Again remember; to calculate the wavelength of the ocean waves; we have:

δ= \frac{3*lamda}{2}

δ= 8.47

8.47 = \frac{3*lamda}{2}

λ = \frac{8.47*2}{3}

λ = 5.65m

3 0
3 years ago
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