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STALIN [3.7K]
3 years ago
11

Which upgrade to a school will most likely reduce the school's consumption of

Chemistry
1 answer:
AlexFokin [52]3 years ago
5 0

Answer: if they use solar collection panels

Explanation:

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6. Which of the following labels for the picture below is correct? a) Solute + solvent = solution b) Solvent + solute = saturati
SVETLANKA909090 [29]

Answer:

answer is a since solute dissolve a solvent to give a solution

4 0
3 years ago
How many formula units make up 19.0 g of magnesium chloride (MgCl2)?
professor190 [17]
To convert the mass of a compound to formula units, the conversion factor is Avogadro's number, 6.022 x10^23 formula units/ mol and its molar mass. In this case, we are given with 19.0 grams of magnesium chloride which has a mass of 95.21 g/mol. Hence the answer is 1.20 x 10^23 formula units.
5 0
4 years ago
What is the volume of an object with a density of 2.6 g/cm³ and a mass of 30.5g?
inessss [21]

Answer:

The answer is

<h2>11.73 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}

From the question

mass of object = 30.5 g

Density = 2.6 g/cm³

The volume is

volume =  \frac{30.5}{2.6}  \\  = 11.7307692...

We have the final answer as

<h3>11.73 mL</h3>

Hope this helps you

5 0
3 years ago
1. Addition of which of the following will increase the solubility of CaCO3 in water? Consider the equilibrium process:
kolbaska11 [484]

Answer: HCl

Explanation:

calcium carbonate dissolves in HCl acid producing CO 2 gas. It will not dissolve in pure water. The Ksp for calcium carbonate in water is 3.4 x 10-9 moldm-3 which is very low. What takes place here is actually a chemical reaction:

CaCO 3 (s) + 2HCl(aq) → CaCl 2 (aq) + H 2CO 3(aq)

This reaction accounts for the solubility of the Calcium carbonate in HCl and not in pure water.

6 0
3 years ago
In the following reaction, what element is gaining mass?
vagabundo [1.1K]

Mg gained mass because it went from being a single element (on the reactant side) to being a molecule (on the product side).

8 0
3 years ago
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