a person on tour has 360 $ for his daily expense. if he extends his tour for 4 days,he has to cut down his daily expense by 3$.
1 answer:
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Answer:
-2.154
Step-by-step explanation:
We are given;
Population mean; μ = 432
Sample mean; x¯ = 425
Sample size; n = 29
standard deviation; σ = 26
Hypothesis is defined as;
Null hypothesis; H0: μ ≥ 432
Alternative hypothesis: Ha: μ < 432
Formula for the test statistic since sample size is less than 30 is;
t = (x¯ - μ)/(σ/√n)
Plugging in the relevant values;
t = (425 - 432)/(26/√29)
t = -1.45
Now,we are given significance level of 0.02; our DF = n - 1 = 29 - 1 = 28
From t-table attached, we can see that at DF of 28 and significance value of 0.02, the critical value is 2.154
However, this is a left tailed test as the rejection region is to the left.
Thus, the critical value of a left tailed test is negative. Thus, in this case our critical value will be -2.154
