3 years ago

What has more kinetic energy 15 kg ball rolling north at 15 m/s or a 15 kg ball rolling backwards at 7m/s

Physics

1 answer:

Setler79 [48]3 years ago

6 0

Answer:

15 kg ball

Explanation:

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If the observed test value of a hypothesis test is outside of the established critical value(s), a researcher would __________.

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3 years ago

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A 100-turn, 3.0-cm-diameter coil is at rest in a horizontal plane. A uniform magnetic field 60%u2218 away from vertical increase

Xelga [282]

Answer:

Induced emf in the coil, E = 0.157 volts

Explanation:

It is given that,

Number of turns, N = 100

Diameter of the coil, d = 3 cm = 0.03 m

Radius of the coil, r = 0.015 m

A uniform magnetic field increases from 0.5 T to 2.5 T in 0.9 s.

Due to this change in magnetic field, an emf is induced in the coil which is given by :

$E=-NA\dfrac{\Delta B}{\Delta t}$

$E=-100\times \pi (0.015)^2\times \dfrac{2.5-0.5}{0.9}$

E = -0.157 volts

Minus sign shows the direction of induced emf in the coil. Hence, the induced emf in the coil is 0.157 volts.

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3 years ago

A plate carries a charge of 3.8 UC, while a rod carries a charge of 1.9 C. How many electrons must be transferred from the plate

frosja888 [35]

Answer:

$N_{electrons}=Q_{transfered}/q_{electron}=5.94*10^{18}electrons$

Explanation:

The total charge is distributed over the two objects:

$Q_{total}/2=(3.8*10^{-6}C+1.9C)/2=0.9500019C\\$

The plate and the rod must have $Q_{total}/2\\$ . So the charge transferred from the plate to the rod is:

$Q_{transfered}=3.8*10^{-6}C-Q_{total}/2=3.8*10^{-6}C-0.9500019C=-0.9499981C\\$

Number of electrons:

$N_{electrons}=Q_{transfered}/q_{electron}=-0.9499981C/(-1.6*10^{-19}C)=5.94*10^{18}electrons$

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3 years ago

Which expression shows the amount of work a 6-kilogram mass is capable of performing if it is dropped from a height of 2 meters?

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The acceleration of gravity is 9.8 m/s^2

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2 years ago

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RoseWind [281]

Answer: $3.6\ kW$

Explanation:

Given

Power Supplied $[tex]P_{input}=4\ kW$ [/tex]

Efficiency of the motor $\neta =90\%$

and $\neta =\dfrac{\text{Power output}}{\text{Power input}}$

$\Rightarrow 0.9=\dfrac{P_{out}}{4}$

$\Rightarrow P=0.9\times 4$

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So, vacuum cleaner delivers a power of $3.6\ kW$

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3 years ago