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Kazeer [188]
3 years ago
11

How does reflection work?

Physics
1 answer:
s344n2d4d5 [400]3 years ago
4 0
All my brain cells has disappeared
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Compute the resistance in ohms of a copper block 5.0 cm long and 0.10 cm2 in cross-sectional area. (ρ = 1.77 × 10-6 ohm-cm)
soldier1979 [14.2K]
R=ρ l/a
l=5 cm
a=0.10 cm²
ρ=1.77×10∧-6 Ωcm
R=(1.77×10∧-6) ×5/0.10
  =8.85 ×10∧-5 Ω

resistance is directly proportional to length and inversly proportional to area of cross section is given by above equation 
4 0
3 years ago
In a thundercloud there may be an electric charge of 26 C near the top of the cloud and −26 C near the bottom of the cloud. If t
strojnjashka [21]

Answer:

869,142,857.1 N

Explanation:

use this formula,

F =  \frac{Q1  Q2 }{4\pi eo  R^{2} }

All the value is given.

6 0
3 years ago
∁=f
Sindrei [870]

Answer:

so you have a question

Explanation:

either way have a nice day

5 0
3 years ago
In Europe the standard voltage in homes is 220 V instead of the 120 V used in the United States. Therefore "100-W" European bulb
Maslowich

Explanation:

In Europe the standard voltage in homes is 220 V instead of the 120 V used in the United States.

100-W European bulb would be intended for use with a 220-V potential difference.

(a) If V = 220 V and P = 100 W

Power :

P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{(220)^2}{100}\\\\R=484\ \Omega

If you bring a "100-W" European bulb home to the untied States, what should be its US power rating. So,

P=\dfrac{V^2}{R}\\\\P=\dfrac{(120)^2}{484}\\\\P=29.75\ W

or

P = 29.8 watts

(b) Let I is the current will the 100-W European bulb draw in normal use in the United States. So,

I=\dfrac{V}{R}\\\\I=\dfrac{120}{484}\\\\I=0.248\ A

Hence, this is the required solution.

3 0
3 years ago
Read 2 more answers
a stone is dropped from top of a tower of 50m high ,simltaneously another stone is thrown upward with a speed of 20m/s find the
aleksklad [387]
At the time that I'll call ' Q ', the height of the stone that was
dropped from the tower is

             H = 50 - (1/2 G Q²) ,

and the height of the stone that was tossed straight up
from the ground is

             H  =  20Q - (1/2 G Q²) .

The stones meet when them's heights are equal,
so that's the time when

                         <span>50 - (1/2 G Q²)  =  20Q - (1/2 G Q²) .

This is looking like it's going to be easy.

Add  </span><span>(1/2 G Q²)  to each side.
Then it says
                                             50  =  20Q

Divide each side by 20:          2.5  =  Q .

And there we are.  The stones pass each other

                                       2.5 seconds

after they are simultaneously launched.
</span>
5 0
3 years ago
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