Answer:
121Sb=57.2%
123Sb=42.8%
Explanation:
We are given that
Atomic mass of 121Sb=120.904 amu
Atomic mass of 123Sb=122.904 amu
Average atomic mass of antimony=121.760 amu
We have to find the percent of each of the isotope.
Let x be the percent of 121Sb and 1-x be the percent of 123Sb.
Using formula of average atomic weight
Average atomic weight=atomic weight of 121Sb
percentage abundance of isotope 121Sb+atomic weight of 123Sb
percentage abundance of isotope 123Sb
Substitute the values
Percentage of 121Sb=
57.2%
Abundance of isotope 123Sb=1-0.572=0.428
Percentage of isotope 123Sb=
42.8%
Answer:
4
Explanation:
friction
weight
normal reaction
force to overcome inertia
Answer:
10 m/s
Explanation:
Given:
Amplitude of atomic vibrations (λ) = 10⁻⁹ cm = 10⁻⁹ × 10⁻² m = 10⁻¹¹ m [1 cm = 10⁻² m]
Frequency of the vibrations (f) = 10¹² Hz
In order to find the atom's maximum speed, we need to make use of the formula that relates speed, frequency and wavelength of the vibration.
Therefore, the formula for maximum speed is given as:
Now, plug in the values given and solve for speed 'v'. This gives,
Therefore, the atom's maximum speed due to thermal energy provided is 10 m/s.
Gold is a pure substance that can be found on the periodic table of elements.
