Answer:
linear charge density = -9.495 × 
C/m
Explanation:
given data
revolutions per second = 1.80 × 
radius = 1.20 cm
solution
we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force
so
- q × E = m × w² × r ..................1
- 9 × 
× 
q = m × w² × r ............2
and w = 
w = 
w = 1.80 × × 
w = 11304000 rad/s
so here from equation 2
- 9 × × 
1.80 × = 1.672 × 
× 11304000² × 0.0120
linear charge density = -9.495 × C/m
Gravitational potential energy can be described as m*g*h (mass times gravity times height).
Originally,
15kg * 9.8m/s^2 *0.3 m = 44.1 kg*m^2/s^2 = 44.1 Joules.
After it is moved to a 1m shelf:
15kg * 9.8m/s * 1 = 147 kg*m^2/s^2= 147 Joules.
To find how much energy was added, we subtract final energy from initial energy:
147 J - 44.1 J = 102.9 Joules.
Answer:
Gravity provides a downward force, resulting in the diver going downward. They speed up like any falling object would, the pull of gravity is a dominant force. (There is a drag force – as a result of moving through the air.)
I cant really say but i believe it is called extinction
Answer:
a = 3,0 m/s²
Explanation:
En este ejercicio se pide calcular la aceleracion del cuerpo, usemos las ecuaciones de cinematica en una dimensión.
v= v₀ + a t
como el corredor parte del reposo si velocidad inicial es cero
v = at
a = v/t
calculemos
a = 12 /4,0
a = 3,0 m/s²
