Answer:
0.5864 m
Explanation:
= 0.705 m
= 10 rpm
= 20.5 rpm
The weights are 0.5864 m apart.
Answer:
Explanation:
energy density can be obtained as
Where,
E is electric field 
K COLOUMB CONSTANT =8.99*10^{9} N -m2 /C2
Q is charge = CV
C is capacitance = 
![=4\pi *8.85*10^{-12} [\frac{10.5*16.5}{16.5 -10.5}]](https://tex.z-dn.net/?f=%3D4%5Cpi%20%2A8.85%2A10%5E%7B-12%7D%20%5B%5Cfrac%7B10.5%2A16.5%7D%7B16.5%20-10.5%7D%5D)
![Q = 3.21*10^{-9} *150 = 4.81*10^{-7] C](https://tex.z-dn.net/?f=Q%20%3D%203.21%2A10%5E%7B-9%7D%20%2A150%20%3D%204.81%2A10%5E%7B-7%5D%20C)
for r = 10.6 cm
E = 2568.34 N/C
Below are the answers:
a. There is a constant magnetic Feld, which means B is constant, so we can rewrite the change in fux as above.Because ΔA is positive, there will be a negative emf in the loop, corresponding to an induced magnetic momentpointing to the left on the page. The current in the loop will be into the page at the top and out of the page at<span>the bottom
</span>V=-Δφ/ Δt = -B·ΔA/ Δ<span>t
b. </span>As the loop’s radius is increasing, we can think about individual electrons in the wire loop as moving radially<span>outward. We’ll consider one in the top of the loop (which is moving up the page). Using the Lorentz ²orce Law
</span>F=q(~v⇥~B)=qvB(ˆy⇥ˆx)=-qvB<span>ˆ
</span>Constant forces pointing into the center of the loop will result in circular orbits (around the wire). Because the<span>force is pointing into the center of the loop, we know we have positive current at that point (into the page).</span>
Since it travels at 21,000 kilometers per hour, you'd just multiply that with 3.5 to get 73,500. So your answer is 73,500.
