Answer:
Explanation:
<h3><u>Given data:</u></h3>
Acceleration = a = 3 m/s²
Force = F = 150 N
<h3><u>Required:</u></h3>
Mass = m = ?
<h3><u>Formula:</u></h3>
F = ma
<h3><u>Solution:</u></h3>
Put the givens in the formula
150 = m (3)
Divide 3 to both sides
150/3 = m
50 kg = m
m = 50 kg
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Answer:
a. 12.12°
b. 412.04 N
Explanation:
Along vertical axis, the equation can be written as
T_1 sin14 + T_2sinA = mg
T_2sinA = mg - T_1sin12.5 ....................... (a)
Along horizontal axis, the equation can be written as
T_2×cosA = T_1×cos12.5 ......................... (b)
(a)/(b) given us
Tan A = (mg - T_1sin12.5) / T_1 cos12.5
= (176 - 413sin12.5) / 413×cos12.5
A = 12.12 °
(b) T2 cosA = T1 cos12.5
T2 = 413cos12.5/cos12.12
= 412.04 N
Answer:
D
Explanation:
I just had this question the answer is D
Answer:
answer is 2 option because more force is applied
Answer:
1.171
Explanation:
if n₁sinΘ₁=n₂sinΘ₂, then n₂=n₁sinΘ₁ / sinΘ₂;
