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Assoli18 [71]
3 years ago
5

Lee pushes horizontally with a force of 75 n on a 36 kg mass for 10 m across a floor. calculate the amount of work lee did. answ

er in units of j.
Physics
2 answers:
svlad2 [7]3 years ago
8 0
To find work, you use the equation: W = Force X Distance X Cos (0 degrees)
Following the Law of Conservation of Energy, energy cannot be destroyed nor created.

So you would do 75 N x 10m x Cos (0 degrees)= 750 J
Marysya12 [62]3 years ago
7 0

Answer:

The work done by Lee is 3528 Joules.

Explanation:

Given that,

Mass of the object, m = 36 kg

Force applied by Lee on the object, F = 75 N

The object moves to a distance, d = 10 m

We need to find the amount of work done by Lee. It is given by the combination of force and displacement of an object. It is given by :

W=F{\cdot} d

W=mg{\cdot} d

W=36\times 9.8\times 10

W = 3528 Joules

So, the work done by Lee is 3528 Joules. Hence, this is the required solution.

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A charge of 6.4x 10^-7 c experiences an electric force of 1.8 x10^-1 N. What is the electric field strength ?
laila [671]
Electric
field strength = Electric force/charge
E = F/q
E = (1.8×10^-1) / (6.4×10^-7)
E = 2.81×10^5 NC^-1

Hope it helped!
5 0
3 years ago
1. Explique con sus palabras por qué el ser humano al nacer es un organismo inacabado, y que influencia ejercen en él las caract
Vlad [161]

Answer:

Todo ser humano, al nacer, es un organismo inacabado en términos tanto físicos como psicoemocionales. Es decir, el humano, al nacer, lo hace sin la posibilidad de autosustentarse en el futuro inmediato: no puede caminar, expresarse, tener pensamiento analítico ni la capacidad de resolver las problemáticas que les afectan.

Ello hace que el humano requiera para su desarrollo de un acompañamiento absoluto por parte de su madre en el período inicial de su vida, tanto para alimentarlo como para transmitirle las nociones básicas de supervivencia; y posteriormente requiera de un entorno social idóneo que le permita desarrollarse emocionalmente para poder vivir normalmente en sociedad.

Además, respecto de sus características físicas, necesita también aprender a caminar, movilizarse y demás atributos físicos que le garanticen un normal desarrollo motor, con lo cual es fundamental que dicha enseñanza provenga también del entorno que lo rodea.

7 0
3 years ago
What is the time constant of a 9.0-nm-thick membrane surrounding a 0.040-mm-diameter spherical cell? Assume the resistivity of t
yawa3891 [41]

Given Information:

Diameter of spherical cell = 0.040 mm

thickness = L = 9 nm

Resistivity =  ρ = 3.6×10⁷ Ω⋅m

Dielectric constant = k = 9.0

Required Information:

time constant = τ = ?

Answer:

time constant = 2.87×10⁻³ seconds

Explanation:

The time constant is given by

τ = RC

Where R is the resistance and C is the capacitance.

We know that resistivity of of any material is given by

ρ = RA/L

R =  ρL/A

Where area of spherical cell is given by

A = 4πr²

A = 4π(d/2)²

A = 4π(0.040×10⁻³/2)²

A = 5.026×10⁻⁹ m²

The resistance becomes

R =  (3.6×10⁷*9×10⁻⁹)/5.026×10⁻⁹

R = 6.45×10⁷ Ω

The capacitance of the cell membrane is given by

C = kεoA/L

Where k = 9 is the dielectric constant and εo = 8.854×10⁻¹² F/m

C = (9*8.854×10⁻¹²*5.026×10⁻⁹)/9×10⁻⁹

C = 44.5 pF

C = 44.5×10⁻¹² F

Therefore, the time constant is

τ = RC

τ = 6.45×10⁷*44.5×10⁻¹²

τ = 2.87×10⁻³ seconds

6 0
3 years ago
Coulomb's law states that the force F of attraction between two oppositely charged particles varies jointly as the magnitude of
Mars2501 [29]

Answer: Force F will be one-sixteenth of the new force when the charges are doubled and distance halved

Explanation:

Let the charges be q1 and q2 and the distance between the charges be 'd'

Mathematical representation of coulombs law will be;

F1=kq1q2/d²...(1)

Where k is the electrostatic constant.

If q1 and q2 is doubled and the distance halved, we will have;

F2 = k(2q1)(2q2)/(d/2)²

F2 = 4kq1q2/(d²/4)

F2 = 16kq1q2/d²...(2)

Dividing equation 1 by 2

F1/F2 = kq1q2/d² ÷ 16kq1q2/d²

F1/F2 = kq1q2/d² × d²/16kq1q2

F1/F2 = 1/16

F1 = 1/16F2

This shows that the force F will be one-sixteenth of the new force when the charges are doubled and distance halved

4 0
3 years ago
What is the electrical force between q2 and q3? Recall that k = 8. 99 × 109 N•meters squared over Coulombs squared. 1. 0 × 1011
nlexa [21]

Force on the particle is defined as the application of the force field of one particle on another particle. the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

<h3>What is electric force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.

\rm F= K\frac{q_2q_3}{r^2}

\rm F= 9\times 10^9 \times \frac{1.6 \times 10^{-13}\times 1.6\times10^{-13}}{(0.5)^2}

\rm F=  - 1. 1 \times 10^{11 }N

Hence the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

To learn more about the electric force refer to the link;

brainly.com/question/1076352

4 0
3 years ago
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