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Assoli18 [71]
3 years ago
5

Lee pushes horizontally with a force of 75 n on a 36 kg mass for 10 m across a floor. calculate the amount of work lee did. answ

er in units of j.
Physics
2 answers:
svlad2 [7]3 years ago
8 0
To find work, you use the equation: W = Force X Distance X Cos (0 degrees)
Following the Law of Conservation of Energy, energy cannot be destroyed nor created.

So you would do 75 N x 10m x Cos (0 degrees)= 750 J
Marysya12 [62]3 years ago
7 0

Answer:

The work done by Lee is 3528 Joules.

Explanation:

Given that,

Mass of the object, m = 36 kg

Force applied by Lee on the object, F = 75 N

The object moves to a distance, d = 10 m

We need to find the amount of work done by Lee. It is given by the combination of force and displacement of an object. It is given by :

W=F{\cdot} d

W=mg{\cdot} d

W=36\times 9.8\times 10

W = 3528 Joules

So, the work done by Lee is 3528 Joules. Hence, this is the required solution.

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Answer: 20.4752789138x x  10^23 atoms
To count how many atoms in moles you need to know Avogadro's number. Avogadro's number dictate that for every mole there is 6.022140857 × 10^23 molecule/atoms.
Then 3.4 moles of helium will be 3.4x 6.022140857 x  10^23 atoms= 20.4752789138x x  10^23 atoms
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Sunitha can type 1800 words in half an hour. What is her typing speed in words per minute?
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Answer:

60words/minute

Explanation:

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Hence her typing speed in words per minute is 60words/minute

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Argue as to why drivint on icy or snowy roads can be dangerous
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Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
stellarik [79]

Answer:

0.243 m/s

Explanation:

From law of conservation of motion,

mu+m'u' = V(m+m')................. Equation 1

Where m = mass of the first car, m' = mass of the second car, initial velocity of the first car, u' = initial velocity of the second car, V = Final velocity of both cars.

make V the subject of the equation

V = (mu+m'u')/(m+m')................. Equation 2

Given: m = 260000 kg, u = 0.32 m/s, m' = 52500 kg, u' = -0.14 m/s

Substitute into equation 2

V = (260000×0.32+52500×(-0.14))/(260000+52500)

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