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d1i1m1o1n [39]
3 years ago
13

Please help that is muh question

Mathematics
1 answer:
Marina86 [1]3 years ago
7 0
Answer:
t=d/350 and d=350*t
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A cylinder is sliced by a plane that is not parallel to the base and intersects only the lateral surface. The resulting cross se
Lady bird [3.3K]

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c. Ellipse

Step-by-step explanation:

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3 years ago
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Complete the equation of the line through ( − 9 , 7 ) and ( − 6 , − 3 ) Use exact numbers. y =
sesenic [268]

Answer:

Step-by-step explanation:

first we need to find the slope using the slope formula :

slope = (y2 - y1) / (x2 - x1)

(-9,7)...x1 = -9 and y1 = 7

(-6,-3)....x2 = -6 and y2 = -3

now we sub

slope = (-3 - 7) / (-6 - (-9) = -10 / (-6 + 9) = -10 / 3

so our slope is -10/3

now we use y = mx + b....with m representing the slope

slope(m) = -10/3

use either of ur points....I will use (-9,7)...x = -9 and y = 7

we are solving for b, the y intercept

now we sub

7 = -10/3(-9) + b

7 = 30 + b

7 - 30 = b

- 23 = b

so ur equation is : y = -10/3x - 23

4 0
4 years ago
How to factor 6n2 - 6n - 12
alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

6n^2-6n-12 = 6(n^2-n-2)

We can set this equal to 0 and factor by using the quadratic formula which is:

x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

So, let's do just that:

6(n^2-n-2) = 0

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}

\frac{-1 \pm \sqrt{9} }{2} = {1, -2}

So, we can write this as:

6n^2 - 6n - 12 = 6(n-1)(n+2)

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

7 0
3 years ago
Por la seguridad de su personal y sus clientes una agencia bancaria se instalara una camara de video en un soporte de pared de m
yulyashka [42]

Answer:

16.24°

Step-by-step explanation:

Are you trying to find the angle of depression from the camera to the cashier?

Assume that the camera is 2.24 m high and the cashier is 7.69 m away.

1. Angle of elevation from cashier

tanθ = 2.24/7.69 = 0.2913

θ = arctan(0.2913) = 16.24°  

2. Angle of depression from camera

∠ of depression = ∠ of elevation = 16.24°

6 0
3 years ago
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