Please help that is muh question
1 answer:
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Answer:
The Proof is given below.
Step-by-step explanation:
Given:
P is the center of Circle
∠ONE ≅ ∠TEN
To Prove:
∠5 ≅ ∠6
Proof:
Exterior Angle Theorem:
Exterior Angle Property of a Triangle states that measure of exterior angle of a triangle is equals to the sum of measures of its interior opposite angles.
STATEMENT REASON
1. So In ΔONE,
1. Exterior Angle Property of a Triangle.
2. Similarly In ΔTEN,
2. Exterior Angle Property of a Triangle.
3. But , ∠ONE ≅ ∠TEN 3. Given
4. And P is the center of circle So
4.radius of same circle
5. ΔPEN is an Isosceles triangle,
∴ ∠ 1 ≅ ∠ 2 5. Isosceles triangle property
6. ∴ ∠5 ≅ ∠6 6. From 3 and 5 Transitive Property.........Proved
( a )pairs of vertical angles :
AGB and EGD
Vertical angles are a pair of opposite angles formed by intersecting lines. Vertical angles are equal in magnitude.
( b ) a pair of adjacent angles :
AGB and BGC
Adjacent angles are two angles that have a common side and a common vertex (corner point) but do not overlap in any way.
(c) Name a pair if supplementary angles :
AGB and BGD
Two angles are called supplementary when their measures add up to 180 degrees.
(d) A pair of complementary angles :
AGF and FGE
Two angles are called complementary when their measures add to 90 degrees.
(e) Find measure of CGD :
( look into the photo attached for better understanding)
CGD = 55°
<em>hope this helps :)</em>
