R\6 = 8 what does r equal?

What is 5/9 in simplest form ?

masha68 [24]

5/9 is in simplest form.

6 0

3 years ago

Which is the largest decimal? Please explain. 0.267 0.530000 0.407 0.000011

Slav-nsk [51]

The largest is 0.530000 because it is closest to 1. The 5 is the largest in the tenths place.

4 0

3 years ago

A new restaurant with 134 seats is being planned. Studies show that 62% of the customers demand a smoke-free area. How many se

zzz [600]

Answer: 100

Step-by-step explanation:

Given : The total number of seats planned in new restaurant =134

The percentage of customers demand a smoke-free area = 62%

It can also be written as $62\%=\dfrac{62}{100}=0.62$

The mean of this binomial distribution will be :-

$\mu=np\\\\\mu=(134)(0.62)=83.08$

Standard deviation:-

$\sigma=\sqrt{np(1-p)}\\\\\Rightarrow\sigma=\sqrt{134(0.62)(0.38)}\approx5.6$

Now, the number of seats should be in the non-smoking area in order to be very sure of having enough seating there :-

$\mu+3\sigma=83.08+3(5.6)=99.88\approx100$

4 0

3 years ago

Use the grouping method to factor the polynomial below completely. x - 4x² + 3x - 12

N76 [4]

Answer:

6xsquare

Step-by-step explanation:

that is my answer

3 0

3 years ago

Read 2 more answers

We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure

STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be $h(t) = -16\cdot t^{2} + 128\cdot t + 320$ , the first and second derivatives are, respectively:

First Derivative

$h'(t) = -32\cdot t +128$

Second Derivative

$h''(t) = -32$

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

$-32\cdot t +128 = 0$

$t = \frac{128}{32}\,s$

$t = 4\,s$ (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

$h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320$

$h(4\,s) = 576\,ft$

The highest altitude that the object reaches is 576 feet.

6 0

4 years ago