Question

What volume in litres will 38gr of F2 occupy at 0.999 bar and 273 K

Answer 1

Answer:

$V=22.68L$

Explanation:

Hello,

In this case, we use the ideal gas equation to compute the volume as shown below:

$PV=nRT\\\\V=\frac{nRT}{P}$

Nonetheless we are given mass, for that reason we must compute the moles of gaseous fluorine (molar mass: 38 g/mol) as shown below:

$n=38 g *\frac{x}{y} \frac{1mol}{38 g} =1mol$

Thus, we compute the volume with the proper ideal gas constant, R:

$V=\frac{1mol*0.083\frac{bar*L}{mol*K}*273K}{0.999bar} \\\\V=22.68L$

Best regards.