The answer is (4) at the cathode, where reduction occurs. The Na+ gains one electron and become Na(l). So the reaction occurs at cathode and is reduction reaction.
Answer:
Specific heat of water = 33.89 KJ
Explanation:
Given:
mass of water = 81 gram
Initial temperature = 0°C
Final temperature = 100°C
Specific heat of water = 4.184
Find:
Required heat Q
Computation:
Q = Mass x Specific heat of water x (Final temperature - Initial temperature)
Q = (81)(4.184)(100-0)
Q = 33,890.4
Specific heat of water = 33.89 KJ
Answer:
<u>Why is it important to keep the two sides of an equation balanced when solving?</u>
If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal. When you solve an equation, you find the value of the variable that makes the equation true.
<u>What other properties do we use to rewrite expressions and equations?</u>
State of matter
Please vote for Brainliest and I hope this helps!
Hello!
The answer is Evaporation!
When you add enough heat to a liquid, it boils turning into a gas. This is called Evaporation
