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3 years ago

5

What is another name for homogeneous mixtures other than solution

1 answer:

Ede4ka [16]3 years ago

4 0

Answer and Explanation:

The answer is solution. However, single-phase alloys are solid metal solutions, and colloidal suspensions are homogenous mixtures that are not solutions. Homogenized milk, for example, is a colloidal suspension that technically meets the definition of a homogenous mixture because the milk fats, though immiscible with the whey (the aqueous phase), are tiny beads evenly distributed through the whey, and do not separate according to density, as they do in non-homogenized milk.

Hope this helps. :)

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If a chlor-alkali cell used a current of 3X10⁴A, how many pounds of Cl₂ would be produced in a typical 8-h operating day?

vova2212 [387]

7 × 10² pounds of Cl₂ would be produced in a typical 8-h operating day.

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us use the balanced chemical equation to measures quantitative relationships and it is to calculate the amount of products and reactants that are given in a reaction.

<h3>What is Balanced chemical equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactants side is equal to the number of atoms on the product side in an equation.

2Cl⁻ (aq) → Cl (g) + 2e⁻

According to stoichiometry, moles of Cl₂

$= (3 \times 10^4\ A) \left (\frac{\frac{C}{s}}{A} \right ) \left (\frac{3600\ s}{h} \right ) (8h) \left (\frac{1\ \text{mol}\ e^{-}}{9.65 \times 10^4\ C} \right ) \left (\frac{1\ \text{mol}\ Cl_2}{2\ \text{mol}\ e^-} \right )$

= 4477 moles

Pounds Cl₂

$= (4477\ \text{moles}\ Cl_2) \left (\frac{70.90\ g\ Cl_2}{\text{mol}} \right ) \left (\frac{1\ kg}{1000\ g} \right ) \left (\frac{2.205\ lb}{1\ kg} \right )$

= 7 × 10² lb

Thus from the above conclusion we can say that 7 × 10² pounds of Cl₂ would be produced in a typical 8-h operating day.

Learn more about Stoichiometry here: brainly.com/question/14935523

#SPJ4

5 0

2 years ago

Cobalt-60 is a strong gamma emitter that has a half- life of 5.26 yr. The co balt-60 in a radiotherapy unit must be replaced whe

Alenkasestr [34]

<u>Answer:</u> The sample of Cobalt-60 isotope must be replaced in January 2027

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = 5.26 years

Putting values in above equation, we get:

$k=\frac{0.693}{5.26yrs}=0.132yrs^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.132yr^{-1}$

t = time taken for decay process = ? yr

$[A_o]$ = initial amount of the sample = 100 grams

[A] = amount left after decay process = (100 - 75) = 25 grams

Putting values in above equation, we get:

$0.132=\frac{2.303}{t}\log\frac{100}{25}\\\\t=10.5yrs$

The original sample was purchased in June 2016

As, June is the 6th month of the year, which means the time period will be $2016+\frac{6}{12}=2016.5$

Adding the time in the original time period, we get:

$2016.5+10.5=2027$

Hence, the sample of Cobalt-60 isotope must be replaced in January 2027

3 0

3 years ago

An atom of 24/11 na decays by gamma decay which atom is left after the decay

hammer [34]

Answer:

Hello There!!

Explanation:

The atom is still 24Na.

hope this helps,have a great day!!

~Pinky~

6 0

3 years ago

How many atoms are in 0.625 moles of ge (atomic mass = 72.59 amu)?

lord [1]

0.625 moles of ge X 6.02x10^23 atoms/ 1 mol of ge equal to 3.76x10^23 atoms of ge, just times with Avogadro.

8 0

3 years ago

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What are three possible blood type alleles?

Keith_Richards [23]

Answer:

Three possible blood type alleles are Iᴬ, Iᴮ and i

Explanation:

Iᴬ, Iᴮ and i are three possible blood type alleles.

Iᴬ and Iᴮ are known as co-dominant, and The i allele is recessive.

Thus, Three possible blood type alleles are Iᴬ, Iᴮ and i

<u>-TheUnknownScientist</u>

8 0

3 years ago

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