Compounding Corner on RxNet is the best reference for more information regarding compounding
<u>Explanation:</u>
RxNet is an open online community, consolidating scientists from the domains of chemistry, biochemistry and expanding industry of drug innovation and improvement. Compounding presents an innovative way for pharmacists to customize prescriptions to suit the requirements of their patients.
The art of compounding employs advanced medicine while still sticking to the roots of the profession of pharmacy. Compounding pharmacies can create unparalleled dosage forms based on patient preferences. Compounded medicines are usually reliable and sufficient for most victims who have spoken to their physician about their wellness.
Answer:
E
Explanation:
Why can a signaling molecule cause different responses in different cells? Different cells have membrane receptors that bind to different sides of the signaling molecule. The transduction process is unique to each cell type; to respond to a signal, different cells require only a similar membrane receptor
The desirable soil pH for corn ranges from 5.8 to 7.0.
Answer:
False
Explanation:
We can see the colors of the rainbow, therefore they are visible.
4.20 mol Al would react completely with 4.20 x (1/2) = 2.10 mol Fe2O3, but there is not that much Fe2O3 present, so Fe2O3 is the limiting reactant. (1.75 mol Fe2O3) x (2/1) x ( 55.8452 g Fe/mol) = 195 g Fe 3 MgO + 2 H3PO4 → Mg3(PO4)2 + 3 H2O (15.0 g MgO) / (40.3045 g MgO/mol) = 0.37217 mol MgO (18.5 g H3PO4) / (97.9953 g H3PO4/mol) = 0.18878 mol H3PO4 0.18878 mol H3PO4 would react completely with 0.18878 x (3/2) = 0.28317 mole of MgO, but there is more MgO present than that, so MgO is in excess and H3PO4 is the limiting reactant. Now we must consider why the problem tells us "17.6g of Mg3(PO4)2 is obtained". The first possibility is that it's just there for the sake of confusion -- in which case ignore it and proceed this way: ((0.37217 mol MgO initially) - (0.28317 mole MgO reacted)) x (40.3045 g MgO/mol) = 3.59 g MgO left over However, if the amount of magnesium phosphate obtained is given because the reaction was stopped before it was complete, the amount obtained governs the amount reacted and the amount left over, so proceed this way: (17.6g Mg3(PO4)2) / (262.8581 g Mg3(PO4)2/mol) x (3/1) = 0.20087 mol MgO reacted ((0.37217 mol MgO initially) - (0.20087 mole MgO reacted)) x (40.3045 g MgO/mol) = 6.90 MgO left over
