Pressure increases with increasing depth. h2=2hh
When gases, fluids, or other solids are in contact with a moving object
heat is produced due to friction.
Answer:
86605.08 N
Explanation:
The equation to calculate the force is:
Force = mass * acceleration
The force and the acceleration does not have the same direction in this case, so we need to decompose the force into its horizontal component, which is the force that will generate the horizontal acceleration:
Force_x = Force * cos(30)
Then, we have that:
Force_x = mass * acceleration
Force * cos(30) = 25000 * 3
Force * 0.866 = 75000
Force = 75000 / 0.866 = 86605.08 N
Answer:
a
The height is 
b
The horizontal distance is 
Explanation:
From the question we are told that
The speed is 
The angle is 
The height of the cannon from the ground is h = 2 m
The distance of the net from the ground is k = 1 m
Generally the maximum height she reaches is mathematically represented as

=> ![H = \frac{(15)^2 [sin (40)]^2 }{2 * 9.8} + 2](https://tex.z-dn.net/?f=H%20%20%3D%20%20%5Cfrac%7B%2815%29%5E2%20%5Bsin%20%2840%29%5D%5E2%20%7D%7B2%20%2A%209.8%7D%20%20%2B%20%202)
=> 
Generally from kinematic equation

Here s is the displacement which is mathematically represented as
s = [-(h-k)]
=> s = -(2-1)
=> s = -1 m
There reason why s = -1 m is because upward motion canceled the downward motion remaining only the distance of the net from the ground which was covered during the first half but not covered during the second half
a = -g = -9.8

So

=> 
using quadratic formula to solve the equation we have

Generally distance covered along the horizontal is

=> 
=> 
Answer:
- 1.42m/s²
Explanation:
Acceleration is defined as the change in velocity of a body with respect to time.
Acceleration = change in velocity/time
Change in velocity = final velocity - initial velocity
Acceleration = final velocity - initial velocity/time
Since she slows her car from 14.0 to 5.5m/s in 6seconds,
Initial velocity = 14m/s
Final velocity = 5.5m/s
Time = 6seconds
Substituting in the given formula, we will have
Acceleration = 5.5 - 14/6
Acceleration = - 8.5/6
Acceleration = - 1.42m/s²
The negative acceleration shows that the car decelerates.