consider the motion of the ball in vertical direction after it rolls off the table
v₀ = initial velocity of the ball in vertical direction = 0 m/s
a = acceleration = acceleration due to gravity = 9.8 m/s²
Y = vertical displacement = height of the table = 0.91 m
t = time spent in air by the ball
Using the kinematics equation
Y = v₀ t + (0.5) a t²
0.91 = 0 t + (0.5) (9.8) t²
t = 0.43 sec
v = final velocity in vertical direction just before it hits the ground
Using the kinematics equation
v = v₀ + at
v = 0 + (9.8) (0.43)
v = 4.21 m/s
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The potential energy of the object depends on
- the height of the object with respect to some reference points,
- the mass of the object,
- the gravitational field the object is in.
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Hope it helps ~
Answer:
Explanation:
The motion of the bullet is a uniformly accelerated motion, therefore we can find its acceleration by using the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the bullet in this problem:
u = 350 m/s is the initial velocity of the bullet
v = 0 is the final velocity (the bullet comes to a stop)
s = 0.125 m is the stopping distance of the bullet
Therefore, by solving the equation for a, we find its acceleration:
And the negative sign tells that the direction of the acceleration is opposite to that of the velocity.
Density = 3/5 = 0.6g/cm^3. Since the density is less than the density of water, which is 1, the object will float.
A sphere??????????
i think thats the answer
