Answer:
The tangential acceleration of the pedal is 0.0301 m/s².
Explanation:
Given that,
Length = 19 cm
Diameter = 23 cm
Time = 10 sec
Initial angular velocity = 65 rpm
Final velocity = 90 rpm
Suppose we need to find the tangential acceleration of the pedal
We need to calculate the tangential acceleration of the pedal
Using formula of tangential acceleration


![a_{t}=\dfrac{23\times10^{-2}}{2}\times\dfrac{90\times\dfrac{2]pi}{60}-65\times\dfrac{2\pi}{60}}{10}](https://tex.z-dn.net/?f=a_%7Bt%7D%3D%5Cdfrac%7B23%5Ctimes10%5E%7B-2%7D%7D%7B2%7D%5Ctimes%5Cdfrac%7B90%5Ctimes%5Cdfrac%7B2%5Dpi%7D%7B60%7D-65%5Ctimes%5Cdfrac%7B2%5Cpi%7D%7B60%7D%7D%7B10%7D)

Hence, The tangential acceleration of the pedal is 0.0301 m/s².
The impact front the fall, depending on the distance, has an effect on the impact of their bones crushing with the pressure from the fall.
Distance of lake a is 200 km at 20 degree north of east
distance between lake a and b is 230 km at 30 degree west of north
now the distance between base and lake b is given as

given that




now the total distance is


now the magnitude of the distance is given as


also the direction is given as


<em>so it is 277.4 km at 74.7 degree North of East</em>
Answer:
L = 2.8 cm
Explanation:
Period T = 4 / 12 = 1/3 s
T = 2π√(L/g)
L = (T/2π)²g
L = ((1/3)/2π)²9.8 = 0.02758... ≈ 2.8 cm