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JulijaS [17]
3 years ago
11

Does a heavier object or a lighter object experience a greater gravitational force?

Physics
1 answer:
aalyn [17]3 years ago
5 0

L l Aigabeera ya q alr  mma grasvdade l aferza uatare ms al amtaeialr lgerio hcaieno q edse pese masth

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How did treating workers well benefit henry ford ??
Diano4ka-milaya [45]
He treated then with care he would get more help or what he needed
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As a person squeezes and applies pressure to the outside of a balloon, air particles inside
mixas84 [53]

The air particle inside the balloon will collide more with each other and the temperature inside the balloon will increase.

As a person squeezed and applies the pressure to the outside of a balloon, the air particle inside the balloon gains energy and collide with each other, the particle of the air also try leave the balloon surface will implies equal pressure on the wall of the balloon, as the pressure outside the balloon increase, the inside pressure will also increase.

7 0
3 years ago
The wavelength of an electron whose velocity is 1.7 Ã 104 m/s and whose mass is 9.1 Ã 10-28 g is ________ m. the wavelength of a
madreJ [45]
<span>Mass of the electron = 9.1 x 10 ^ -28g = 9.1 x 10 ^ -31kg Velocity of the electron = 1.7 x 10 ^ 4 We have Planck Constant h = 6.626 x 10 ^ -34 Wavelength of the electron w = h/mv w = 6.626 x 10 ^ -34 / ((9.1 x 10 ^ -31)(1.7 x 10 ^ 4)) = 6.626 x 10 ^ -34 / 15.47 x 10 ^ -27 = 0.428312 x 10 ^ -7 = 4.28 x 10 ^ -8 m</span>
4 0
3 years ago
Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT include
Ket [755]

Answer:

E =  1.64 x 10⁶ V/m

Explanation:

The electric field in the region between the plates can be given by the following formula:

E = \frac{\Delta V}{d}

where,

E = Electric Field = ?

ΔV = Poetential Difference across the plates = 23 KV = 23000 V

d = distance between plates = 1.4 cm = 0.014 m

Therefore, using these values in the equation, we get:

E = \frac{23000\ V}{0.014\ m}

<u>E =  1.64 x 10⁶ V/m</u>

5 0
3 years ago
g During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxi
Alisiya [41]

Answer:

The force is F = 0.1441 \  N

Explanation:

From the question we are told that

   The volume of blood ejected is  V_b  =  65cm^3 = 65*10^{-6} \  m^3

    The velocity of the ejected blood is  v  = 98 cm/ s = 0.98 \  m/s

    The mass density of blood is  \rho = 1060 \  kg/m^3

    The heart rate is  R  =  61 bpm(beats \  per \  miunite) = \frac{61}{60} = 1.0667\  bps

Generally the average force exerted is mathematically represented as

     F = 2 *  \rho *  V_b *  R *  v

=>   F = 2 * 1060  *  (65*10^{-6}) *1.0667   *   0.98

=>   F = 0.1441 \  N    

8 0
3 years ago
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