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Ber [7]
3 years ago
12

Comparing the 2-bromobutane + methoxide and 2-bromobutane + t-butoxide reactions, choose the statements that BEST describe the d

ata and mechanism. a. the mechanism for this reaction is E2 b. an increase in 1-butene was observed when t-butoxide was used c. an increase in 1-butene was observed when methoxide was used d. the mechanism for this reaction is E1 e. no significant difference was observed
Chemistry
1 answer:
Elina [12.6K]3 years ago
8 0

Answer:

an increase in 1-butene was observed when t-butoxide was used

Explanation:

When a base reacts with an alkyl halide, an elimination product is formed. This reaction is an E2 reaction.

Here we are to compare the reaction of two different bases with one substrate; 2-bromobutane. Both reactions occur by the E2 mechanism but follow different transition states due to the size of the base.

The Saytzeff product, 2-butene, is obtained when the methoxide is used while the non Saytzeff product, 1-butene, is obtained when t-butoxide is used.

The Saytzeff rule is reliable in predicting the major products of simple elimination reactions of alkyl halides given the fact that a small/strong bases is used for the elimination reaction. Therefore hydroxide, methoxide and ethoxide bases give similar results for the same alkyl halide substrate. Bulky bases such as tert-butoxide tend to yield a higher percentage of the non Saytzeff product and this is usually attributed to steric hindrance.

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When a supply of hydrogen gas is held in a 4 liter container at 47°C it exerts a pressure
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Explanation:

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3 years ago
Compound Y has a distribution coefficient of 4.0 when extracted from water with chloroform, with Y being more soluble in chlorof
Aleks04 [339]

Answer:

There are needed 3 extractions to extract at least 95%

Explanation:

The distribution coefficient of a compound is defined as the ratio in concentration of the compound in the organic solvent and the concentration in the aqueous solution:

K = Concentration organic solvent / Concentration in water

Assuming as initial amount of the organic solvent: 100% and X as the amount of Y that is extracted

<em>First extraction:</em>

4 = X / 10mL / (100-X) / 50mL

4 = 50X / 1000-X

4000 - 4X = 50X

4000 = 54X

X = 74.1%

In the first extraction, 74.1% of Y is extracted

And will remain: 100 - 74.1 = 25.9%

<em>Second extraction:</em>

4 = X / 10mL / (25.9-X) / 50mL

4 = 50X / 259-X

1036 - 4X = 50X

1036 = 54X

X = 19.2%

In the second extraction, 19.2% of Y is extracted

And will remain: 25.9 - 19.2 = 6.7%

<em>Third extraction</em>

4 = X / 10mL / (6.7-X) / 50mL

4 = 50X / 67-X

268 - 4X = 50X

268 = 54X

X = 5.0%

In the first extraction, 5.0% of Y is extracted

And are extracted:

74.1% + 19.2% + 5.0% = 98.3%

That means there are needed 3 extractions to extract at least 95%

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2 years ago
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Answer:

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Explanation:

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What is the value for the reaction: N2(g) + 2 O2(g) --&gt; N2O4(g) in terms of K values from the reactions:
Valentin [98]

Answer : The correct expression will be:

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Explanation :

The chemical reactions are :

(1) \frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)\rightleftharpoons NO(g) K_1

(2) 2NO(g)+O_2(g)\rightleftharpoons N_2O_4(g) K_2

The final chemical reaction is :

N_2(g)+2O_2(g)\rightleftharpoons N_2O_4 K=?

Now we have to calculate the value of K for the final reaction.

Now equation 1 is multiply by 2 and then add both the reaction we get the value of 'K'.

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

If the two equations are added then equilibrium constant will be multiplied.

Thus, the value of 'K' will be:

K=(K_1)^2\times K_2

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The discovery of the 118 chemical element known to exist us of 2021

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