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Galina-37 [17]
3 years ago
12

Let g = 3. evaluate 12 g⋅(9÷ g.

Mathematics
1 answer:
swat323 years ago
4 0
With g=3
Just replace every g with a 3.
So the equations becomes:
12g·(9÷g)=12(3)·(9÷(3))

This can also be written in the form:
\frac{12(3)9}{3}

Cancelling out the 3's:
12·9=108

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Answer:

The amount of steel used = 94.38 m^{2}

Step-by-step explanation:

Height of the tank = 4.5 m.

Diameter of the tank = 4.2 m.

But,

radius = \frac{diameter}{2}

           = \frac{4.2}{2}

radius  = 2.1 m

Total surface area of a cylinder = 2\pirh + 2\pir^{2}

                                      = 2\pir(r + h)

                                      = 2 x \frac{22}{7} x 2.1 (2.1 + 4.5)

                                      = 44 x 0.3 (6.6)

                                      = 87.12

Total surface area of a cylinder = 87.12 m^{2}

Since \frac{1}{12} of the steel was wasted, then;

\frac{1}{12} x 87.12 = 7.26 m^{2}

Actual area of steel sheet used = 87.12 + 7.26

                                                     = 94.38 m^{2}

Thus, 94.38 m^{2} of steel was used in making the tank.

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