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3 years ago

Why hurricane is dangerous?

Physics

2 answers:

Crazy boy [7]3 years ago

8 0

Answer:

Hurricanes are dangerous because they often carry high winds, in which destroy our homes and other recreational buildings. They also cause flooding, which is a threat to crops, animals, and shelters.

Explanation:

If you enjoyed my answer I would very much appreciate a brainliest. Thank you, and have a great day.

~Kai~

Olin [163]3 years ago

3 0

Because you can die from the hurricane that’s why it is dangerous

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While the change in blank will remain the same during a collision, the force needed to bring an object to a stop can be blank if

Ahat [919]

Explanation :

There are two types of collision i.e. elastic and elastic collision.

Elastic collision : In this type of collision, the total momentum and the kinetic energy of the particles remains constant.
Inelastic collision : In this type of collision, only the momentum remains constant while there is some loss of kinetic energy occurs.

From Newton's second law,

F = m a

a is the rate of change of velocity.

$F=m\dfrac{v}{t}$

There is a inverse relation between the force and the time of collision.

The change in momentum will remain the same during a collision, the force needed to bring an object to a stop can be increased if the time of the collision is decreased.

6 0

3 years ago

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Aleksandr-060686 [28]

Answer:

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3 years ago

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If the pressure on a 1.04L of a sample of gas is doubled at constant temperature , what will be the new volume of the gas?

Juliette [100K]

Answer:

Final volume is equal to 0.52 L

Explanation:

We have given initially the volume is equal to $V_1=1.04L$

Let the initial pressure is $P_1$

At constant temperature $P_1V_1=P_2V_2$ , here $P_1,V_1$ is initial pressure and initial volume respectively and $P_2,V_2$ is final pressure and final volume respectively

Now pressure is doubled so final pressure $P_2=2P_1$

So $P_1\times 1.04=2P_1\times V_2$

$V_2=0.52L$

So final volume is equal to 0.52 L

5 0

3 years ago

Now consider the case in which the object is between the lens and the focal point. Trace the P ray (use the label P1P1P_1 for th

luda_lava [24]

Answer:

1 / f = 1 / p + 1 / q

Explanation:

For this exercise we will use two methods, an analytical method which is to use the constructor equation

1 / f = 1 / p + 1 / q

where f is the focal length, positive for converging lenses and negative for diverging lenses, p and q are the distance to the object and the image respectively

m = h’/ h = - q / p

where m is the magnification, h ’and h are the height of the image and the object.

We will also use a graphical method, where three rays will be traded

1) A ray that passes through the center of the lens and should not

2) a ray that passes through the focal length and comes out parallel to the lens

3) A ray that is horizontal and comes out through the focal from the other side

for this second method see the attachment

5 0

4 years ago

2. Am 80.0 kg astronaut is training for accelerations that he will experience upon re-entry to earth’s gravity from space. He is

AlexFokin [52]

Answer:

a) v = 26.2 m / s, b) acceleration is radial, a = 27.4 m / s², c) a = 2.8 g and

d) a = - 8.73 10⁻² m / s², τ = 1.09 10⁴ N m

Explanation:

a) For this exercise we can use the relationships between rotational and linear motion

v = w r

let's reduce the magnitudes to the SI system

w = 10 rpm (2pi rad / 1 rev) 1 min / 60s) = 1,047 rad / s

r = 25.0 m

let's calculate

v = 1.047 25.0

v = 26.2 m / s

b) When the body is rotating at constant speed, the relationship must be perpendicular to the speed, therefore the direction of acceleration is radial, that is, towards the center of the circle and its magnitude is

a = v² / r

a = 26.2²/25

a = 27.4 m / s²

c) Let's look for the relationship between the centripetal acceleration and the acceleration due to gravity

a / g = 27.4 / 9.8

a / g = 2.8

a = 2.8 g

d) let's find the deceleration and torque to stop the centripette in 5 min

t = 5 min (60 s / 1min) = 300 s

let's use the rotational kinematics relations

w = w₀ + α t

initial angular velocity is wo = 1,047 rad / s and the final as is stop do w = 0

α = - w₀ / t

α = - 1,047 / 300

α = -3.49 10⁻³ rad / s²

angular and linear are related

a = α r

a = -3.49 10⁻³ 25

a = - 8.73 10⁻² m / s²

the negative sign indicates that the acceleration is stopping the movement

torque is

τ = F r

The force can be found with Newton's second law

F = m a

we substitute

τ = m a r

τ = 5000.0 8.73 10⁻² 25

τ = 1.09 10⁴ N m

7 0

3 years ago