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antiseptic1488 [7]
3 years ago
5

While the change in blank will remain the same during a collision, the force needed to bring an object to a stop can be blank if

the time if collision is blank
Physics
2 answers:
Ahat [919]3 years ago
6 0

Explanation :

There are two types of collision i.e. elastic and elastic collision.

  • Elastic collision : In this type of collision, the total momentum and the kinetic energy of the particles remains constant.
  • Inelastic collision : In this type of collision, only the momentum remains constant while there is some loss of kinetic energy occurs.

From Newton's second law,

F = m a

a is the rate of change of velocity.

F=m\dfrac{v}{t}

There is a inverse relation between the force and the time of collision.

The change in <em><u>momentum</u></em> will remain the same during a collision, the force needed to bring an object to a stop can be <em><u>increased</u></em> if the time of the collision is <u><em>decreased</em></u>.

deff fn [24]3 years ago
5 0

Answer:momentum,decreased and increased

Explanation:

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Sarah is measuring how fast a marble rolls down a ramp when she changes the height of the ramp. W hitch type of graph would most
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The type of graph that would most appropriately display Sarah's data is a line graph.

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8 0
2 years ago
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laila [671]

Answer:

d

Explanation:

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4 0
3 years ago
0.3-L glass of water at 20C is to be cooled with ice to 5C. Determine how much ice needs to be added to the water, in grams, i
abruzzese [7]

Answer:

a. m_i_c_e=54.6g\\b. m_i_c_e=48.7g\\m_c_o_l_d_w_a_t_e_r=900g

Explanation:

First we need to state our assumptions:

Thermal properties of ice and water are constant, heat transfer to the glass is negligible, Heat of ice h_i_f=333.7KJkg

Mass of water,m_w=\rho V =1\times0.3=0.3Kg.

Energy balance for the ice-water system is defined as

E_i_n-E_o_u_t=\bigtriangleup E_s_y_s\\0=\bigtriangleup U=\bigtriangleup U_i_c_e+\bigtriangleup U_w

a.The mass of ice at 0\textdegree C is defined as:

[mc(0-T_1)+mh_i_f+mc(T_2-0)]_i_c_e+[mc(T_2-T_1)]_w=0\\\\m_i_c_e[0+333.7+418\times(5-0)]+0.3\times4.18\times(5-20)=0\\m_i_c_e=0.0546Kg=54.6g

b.Mass of ice at 20\textdegree C is defined as:

[mc(0-T_1)+mh_i_f+mc(T_2-0)]_i_c_e+[mc(T_2-T_1)]_w=0\\\\m_i_c_e[2.11\times(0-(20))+333.7+4.18\times(5-0)]+0.3\times4.18\times(5-20)=0\\\\m_i_c_e=0.0487Kg=48.7g

c.Mass of cooled water at T_c_w=0\textdegree C

\bigtriangleup U_c_w+\bigtriangleup U_w=0

[mc(T_2-T_1)]_c_w+[mc(T_2-T_1)]_w=0\\m_c_w\times4.18\times(5-0)+0.3\times4.18\times(5-20)\\m_c_w=0.9kg=900g

8 0
3 years ago
What is the value of g
Mariana [72]
It depends on the environment around you ... the number and size of
the masses around you, and your distance from their center of mass.

If you happen to be on the surface of the Earth, then

                       g  =  9.8 m/s²
       or
                       g  =  9.8 newton/kilogram .

It's different on other planets.  Be sure to look it up
before you leave, so you'll know what to expect.
5 0
4 years ago
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