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Lostsunrise [7]
3 years ago
10

If the pressure on a 1.04L of a sample of gas is doubled at constant temperature , what will be the new volume of the gas?

Physics
1 answer:
Juliette [100K]3 years ago
5 0

Answer:

Final volume is equal to 0.52 L

Explanation:

We have given initially the volume is equal to V_1=1.04L

Let the initial pressure is P_1

At constant temperature P_1V_1=P_2V_2, here P_1,V_1 is initial pressure and initial volume respectively and P_2,V_2 is final pressure and final volume respectively

Now pressure is doubled so final pressure P_2=2P_1

So P_1\times 1.04=2P_1\times V_2

V_2=0.52L

So final volume is equal to 0.52 L

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Answer:

The gravitational potential energy of the man

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80 × 9.8 x 60 ( kg ×m^2/s^2)

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Hope it helps

4 0
3 years ago
A weather balloon is designed to expand to a maximum radius of 24 m at its working altitude, where the air pressure is 0.030 atm
nlexa [21]

Answer:

<em>Radius at liftoff 8.98 m</em>

Explanation:

At the working altitude;

maximum radius = 24 m

air pressure = 0.030 atm

air temperature = 200 K

At liftoff;

temperature = 349 K

pressure = 1 atm

radius = ?

<em>First, we assume balloon is spherical in nature,</em>

<em>and that the working gas obeys the gas laws.</em>

from the radius, we can find the volume of the balloon at working atmosphere.

Volume of a sphere = \frac{4}{3} \pi r^{3}

volume of balloon = \frac{4}{3} x 3.142 x 24^{3} = 57913.34 m^3

using the gas equation,

\frac{P1V1}{T1} = \frac{P2V2}{T2}

<em>The subscript 1 indicates the properties of the gas at working altitude, and the subscript 2 indicates properties of the gas at liftoff.</em>

imputing values, we have

\frac{0.03*57913.34}{200} = \frac{1*V2}{349}

0.03 x 57913.34 x 349 = 200V2

V2 = 606352.67/200 = <em>3031.76 m^3  this is the volume occupied by the gas in the balloon at liftoff.</em>

from the formula volume of a sphere,

V =  \frac{4}{3} \pi r^{3} =  \frac{4}{3} x 3.142 x r^{3} = 3031.76

4.19r^{3}  = 3031.76

r^{3} = 3031.76/4.19  

radius r of the balloon on liftoff = \sqrt[3]{723.57} = <em>8.98 m</em>

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