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Lostsunrise [7]
3 years ago
10

If the pressure on a 1.04L of a sample of gas is doubled at constant temperature , what will be the new volume of the gas?

Physics
1 answer:
Juliette [100K]3 years ago
5 0

Answer:

Final volume is equal to 0.52 L

Explanation:

We have given initially the volume is equal to V_1=1.04L

Let the initial pressure is P_1

At constant temperature P_1V_1=P_2V_2, here P_1,V_1 is initial pressure and initial volume respectively and P_2,V_2 is final pressure and final volume respectively

Now pressure is doubled so final pressure P_2=2P_1

So P_1\times 1.04=2P_1\times V_2

V_2=0.52L

So final volume is equal to 0.52 L

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V125BC [204]
Change in volume = mass x coefficient of linear expansion x change in temperature
.002 x .0001802 x 30 = .000010812

initial volume + change in volume = Final volume
.002 + .000010812 = .002010812 m cubed
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3 years ago
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What is strain?
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Answer:

C) The ratio of the change in an object's length to its original length when stretched or compressed.

Explanation:

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Strain = Change in Length/Origin Length

Hence, it can be described as the percentile of change in the dimension with respect to the original dimension. So, whenever a tensile or a compressive force is applied on a body, its length changes. The ratio of this change to original length is called strain. So, the correct option is:

C) <u>The ratio of the change in an object's length to its original length when stretched or compressed.</u>

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3 years ago
A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0
otez555 [7]

The given question is incomplete. The complete question is as follows.

A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0.90 m/s each second. The push force has a horizontal component of 20 N and a vertical component of 25 N downward. Calculate the coefficient of kinetic friction between the box and the floor.

Explanation:

The given data is as follows.

    F_{1} = 20 N, F_{2} = 25 N, a = -0.9 m/s^{2}

             W = 83 N

         m = \frac{83}{9.81}

             = 8.46

Now, we will balance the forces along the y-component as follows.

       N = W + F_{2}

           = 83 + 25 = 108 N

Now, balancing the forces along the x component as follows.

       F_{1} - F_{r} = ma

        20 - F_{r} = 8.46 \times (-0.9)

             F_{r} = 7.614 N

Also, we know that relation between force and coefficient of friction is as follows.

             F_{r} = \mu \times N

          \mu = \frac{F_{r}}{N}

                    = \frac{7.614}{108}

                    = 0.0705

Thus, we can conclude that the coefficient of kinetic friction between the box and the floor is 0.0705.

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3 years ago
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Answer:

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Explanation:

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<u>Now the amount of heat energy required:</u>

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Theyre all in constant motion

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