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myrzilka [38]
3 years ago
12

Calculate the energy needed to heat 10.5 g ice at -20.0 °C to liquid water at 75.0 °C. The heat of vaporization of water = 2257

J/g, the heat of fusion of water = 334 J/g, the specific heat capacity of water = 4.18 J/g·°C, and the specific heat capacity of ice = 2.06 J/g·°C.
Chemistry
1 answer:
lawyer [7]3 years ago
3 0

Answer:

= 7234.5Joules

Explanation:

Q = (mcΔT)ice + (mΔH)melting +(mcΔT)water

= (10.5g)(2.06J/g°C)[0°C-(-20°C)+(10.5g)(2257J/g)+(10.5g)(4.184J/g°C(75°C - 0°C)

= [(10.5)(2.06)(20) + (10.5)(2257) + (10.5)(4.184)(75)]J

= 432.6J + 3507J + 3294.9J

= 7234.5Joules

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Answer: the coefficient of volume expansion of glass = 0.86/(1000 * 52) = 0.00001654 per degree.

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1) When 6.97 grams of sodium(s) react with excess water(l), 56.0 kJ of energy are evolved.

2) When 10.4 grams of carbon monoxide(g) react with excess water(l), 1.04 kJ of energy are absorbed.

Explanation:

1) The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g).

2 Na(s) + 2H₂O(l) ⇒ 2NaOH(aq) + H₂(g) ΔH = -369 kJ

The enthalpy of the reaction is negative, which means that 369 kJ of energy are evolved per 2 moles of sodium. The energy evolved for 6.97 g of Na (molar mass 22.98 g/mol) is:

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2) The following thermochemical equation is for the reaction of carbon monoxide(g) with water(l) to form carbon dioxide(g) and hydrogen(g).

CO(g) + H₂O(l) ⇒ CO₂(g) + H₂(g)  ΔH = 2.80 kJ

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