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zysi [14]
3 years ago
7

this is how i made the map , i’m not sure where to put the symbols but can someone help me now answer the last few questions i p

osted for it question 3,4,5 and 6 please

Physics
1 answer:
N76 [4]3 years ago
8 0

Answer:

hi my name is bill im here to help no problem 1+1=2

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To determine an athlete's body fat, she is weighed first in air and then again while she's completely underwater. it is found th
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The difference in weight is due to the displacement of water (the buoyancy of water is acting on the athlete thus giving her smaller weight).<span>

The amount of weight displaced or the amount of buoyant force is: </span>

Fb = 690 N - 48 N

Fb = 642 N

From newtons law, F = m*g. Using this formula, we can calculate for the mass of water displaced:

m of water displaced = 642N / 9.8m/s^2

m of water displaced = 65.5 kg

Assuming a water density of 1 kg/L, and using the formula volume = mass/density:

V of water displaced = 65.5kg / 1kg/L = 65.5 L

The volume of water displaced is equal to the volume of athlete. Therefore:

V of athlete = 65.5 L

The mass of athlete can also be calculated using, F = m*g

m of athlete = 690 N/ 9.8m/s^2

m of athlete = 70.41 kg

 

Knowing the volume and mass of athlete, her average density is therefore:

average density = 70.41 kg / 65.5 L

<span>average density = 1.07 kg/L = 1.07 g/mL</span>

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3 years ago
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A 0.050 kg toy truck moving right at 0.20 m/s collided with a toy car weighing 0.015 kg initially at rest, on a frictionless tra
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Answer:

0.1667 m/s

Explanation:

m1V1 + m2V2 = m1V3 + m2V4

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When an electron moves 2.5 m in the direction of an electric field, the change in electrical potential energy of the electron is
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In the field of electromagnetism, when two charged plates that are situated opposite to each other by a certain distance, it forms an energy called the electric field. This energy is due to the difference in potential energy with respect to distance. Thus,

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The electric field that caused the change in potential energy is equal to 199.73 Newtons per Coulomb.
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