150n-1,200 Determina su sueldo si vende, 5, 9 y 12 pantallas.

Help,anyone can help me do quetion.

Digiron [165]

Answer:

Step-by-step explanation:

PQRS is a parallelogram with QR = 6 cm, QT = 3 cm and ∠PSR = 115°.

a). By the property of a parallelogram,

"Diagonals of a parallelogram bisect each other"

QT = TS

QS = 2(QT)

= 2(3)

= 6 cm

b). "Adjacent angles of a parallelogram are supplementary"

m∠PSR + m∠SRQ = 180°

115° + m∠SRQ = 180°

m∠SRQ = 65°

c). Since, SQ = SR = 6 cm

m∠QSR = m∠SRQ [Opposite angles of the equal sides of an isosceles triangle]

m∠QSR = 65°

By applying triangle sum theorem in ΔQSR,

m∠SQR + m∠QRS + m∠QSR = 180°

m∠SQR + 65° + 65° = 180°

m∠SQR = 50°

7 0

3 years ago

Please help math questions put number with answers please

natita [175]

Answer:

See below for answers

Step-by-step explanation:

Problem 1

$\frac{1}{sin\theta}=2cos\theta\: ; \: 0\leq\theta < 2\pi\\\\1=2sin\theta cos\theta\\\\1=sin2\theta\\\\\frac{\pi}{2}+2\pi n=2\theta\\ \\\frac{\pi}{4}+\pi n=\theta\\ \\\theta=\bigr\{\frac{\pi}{4},\frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\bigr\}$

Therefore, the second option is correct.

Problem 2

$cos(2x)+1=sin(x)+2\:;\: 0\leq x < 2\pi\\\\1-2sin^2x+1=sin(x)+2\\\\-2sin^2x=sin(x)\\\\0=2sin^2x+sinx\\\\0=sinx(2sinx+1)$

$0=sinx\\\\x=\pi n\\\\x=0,\pi$

$0=2sinx+1\\\\-1=2sinx\\\\-\frac{1}{2}=sinx\\ \\x=\frac{7\pi}{6}+2\pi n,\frac{11\pi}{6}+2\pi n\\\\x=\frac{7\pi}{6},\frac{11\pi}{6}$

Therefore, the solution set is $x=\bigr\{0,\pi,\frac{7\pi}{6},\frac{11\pi}{6}\bigr\}$ , making the second option correct.

Problem 3

$2cos^2x=-cosx\: ;\: 0^\circ\leq x < 360^\circ\\\\2cos^2x+cosx=0\\\\cosx(2cosx+1)=0$

$cosx=0\\\\x=\frac{\pi}{2}+\pi n\\ \\x=90^\circ+180n^\circ\\\\x=90^\circ,270^\circ$

$2cosx+1=0\\\\2cosx=-1\\\\cosx=-\frac{1}{2}\\\\x=\frac{2\pi}{3}+2\pi n,\frac{4\pi}{3}+2\pi n\\ \\x=120^\circ+360n^\circ,240^\circ+360n^\circ\\\\x=120^\circ,240^\circ$

Therefore, the solution set is $x=\bigr\{90^\circ,120^\circ,240^\circ,270^\circ\bigr\}$ , making the fourth option correct

7 0

2 years ago

On a scale drawing of an office space floor plan...

ki77a [65]

Answer: 16. 21ft

17. 116.67mi or ≈117mi

18. 1,377,795in or 3,499.993m or ≈3500m

How we would calculate each of these: For number 16, you would set up a proportion of 1/3=7/x and then simplify this to 1x=21 which results in you dividing 1 from both sides of the equation and getting 21 as x, or the amount of feet. For number 17, you would do the same thing except with the different numbers. You set up another proportion. 3/50=7/x and then simplify to 3x=350. Divide the 3 on both sides and you get x=116.67mi to which you can round to 117mi if you like. For number 18, you must convert the 3.5 kilometers to inches and get 1,377,795in and then you can convert those inches into meters which would be 3,499.993m or you can round it to around 3500m.

3 0

3 years ago

Solve:2x +7=3 show answer and working out

ivolga24 [154]

3-7= -4

2×-4= -2

I think i did that right...

5 0

3 years ago

Read 2 more answers

Identify the reflection rule on a coordinate plane that verifies that triangle A(-1,7), B(6,5), C(-2,2) and A'(-1,-7), B'(6,-5),

malfutka [58]

Answer:

Option B is correct.

The reflection rule is followed here is, $(x,y) \rightarrow (x, -y)$ .

Explanation:

Since, the triangle is reflected over the x-axis , then only y- coordinates will get changed but the x coordinates will remain the same.

$A(-1,7) \rightarrow A'(-1,-7)$

$B(6,5) \rightarrow B'(6,-5)$

$C(-2,2) \rightarrow C'(-2,-2)$

Therefore, the only reflection rule on the coordinate plane that verifies the triangle are congruent when reflected over x-axis is, $(x,y) \rightarrow (x, -y)$

3 0

4 years ago