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bixtya [17]
3 years ago
7

PLS HELP THIS IS URGENT LIKE AN ASPA QUESTION THAT NEEDS AND ANSWER PLS HELP

Chemistry
2 answers:
Blizzard [7]3 years ago
7 0
40% at wave lengths of infrared (IR) or longer. 50% at visible wave lengths and 10% at wave lengths of ultra violet (UV) or shorter.
I hope this is what you were asking.
Rudiy273 years ago
4 0
I’m pretty sure it’s 80% i had the same question when i did an exam and i got it right so yeah
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If you burn 52.0 g of hydrogen and produce 465 g of water, how much oxygen reacted?
Nadusha1986 [10]
Well, since matter doesn't simply poof into existence and water is H2O, 465g of water is a combination of 52.0g of H and 413g O
7 0
4 years ago
Using the same sample of gas (P1 = 565 torr , T1 = 27 ∘C ), we wish to change the pressure to 5650 torr with no accompanying cha
Stels [109]

Answer:

2726.85 °C

Explanation:

Given data:

Initial pressure = 565 torr

Initial temperature = 27°C

Final temperature = ?

Final pressure = 5650 torr

Solution:

Initial temperature = 27°C (27+273 = 300 K)

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

T₂  = P₂T₁ /P₁

T₂  = 5650 torr × 300 K / 565 torr

T₂  = 1695000 torr. K /565 torr

T₂ = 3000 K

Kelvin to degree Celsius:

3000 K - 273.15 = 2726.85 °C

4 0
3 years ago
PLEASE HELP, NO BOTS PLEASE
aleksandrvk [35]
Protons: 7
electrons: 7
neutrons: 7
4 0
3 years ago
Read 2 more answers
You have 17 liters of gas at STP. If the temperature rises to 94C and while the volume decreases to 12 liters, what will the ne
fenix001 [56]

Answer:

P_2=1.90atm

Explanation:

Hello!

In this case, according to the ideal gas equation ratio for two states:

\frac{P_1V_1}{P_2V_2} =\frac{n_1RT_1}{n_2RT_2}

Whereas both n and R are cancelled out as they don't change, we obtain:

\frac{P_1V_1}{P_2V_2} =\frac{T_1}{T_2}

Thus, by solving for the final pressure, we obtain:

\frac{P_2V_2}{P_1V_1} =\frac{T_2}{T_1}\\\\P_2=\frac{T_2P_1V_1}{V_2T_1}

Now, since initial conditions are 1.00 atm, 273.15 K and 17 L and final temperature and volume are 94 + 273 = 367 K and 12 L respectively, the resulting pressure turns out to be:

P_2=\frac{367K*1.00atm*17L}{12L*273.15K}\\\\P_2=1.90atm

Best regards!

7 0
3 years ago
How many elements had been discovered by 1860
UkoKoshka [18]

60 elements! I don't exactly know every element known, so if you are asking that, please tell us, but what I do know is that there were 60 elements in the periodic table by 1860.

5 0
3 years ago
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