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3 years ago

Why do different elements make different color flames when you burn them?

1 answer:

7 0

When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.

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When does carbon dioxide absorb the most heat energy

bonufazy [111]

Answer:

Carbon dioxide absorbs the most heat energy during SUBLIMATION

Explanation:

Carbon dioxide absorbs the most heat energy during SUBLIMATION

7 0

4 years ago

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Which gas would have the slowest rate of diffusion, assuming that all gases are at the same temperature?

Iteru [2.4K]

Answer: radon (atomic mass 222 amu

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

atomic mass of krypton= 83.8 amu

atomic mass of argon= 39.95 amu

atomic mass of xenon = 131.3 amu

atomic mass of radon= 222 amu

Thus as atomic mass of radon is highest, its rate of diffusion is slowest.

7 0

4 years ago

The number of wavelengths in a given unit of time can be calculated and measured as the wave’s

kykrilka [37]

The answer is Frequency.

8 0

4 years ago

Solutions of Cu2+ turn blue litmus red because of the equilibrium: Cu(H2O)62+(aq) + H2O(l) ↔ Cu(H2O)5(OH)+(aq) + H3O+(aq) for wh

Elanso [62]

Answer: The pH of 0.10 M $Cu(NO_{3})_{2}(aq)$ is 4.49.

Explanation:

Given: Initial concentration of $Cu(H_{2}O)^{2+}_{6}$ = 0.10 M

$K_{a} = 1.0 \times 10^{-8}$

Let us assume that amount of $Cu(H_{2}O)^{2+}_{6}$ dissociates is x. So, ICE table for dissociation of $Cu(H_{2}O)^{2+}_{6}$ is as follows.

$Cu(H_{2}O)^{2+}_{6} \rightleftharpoons [Cu(H_{2}O)_{5}(OH)]^{+} + H_{3}O^{+}$

Initial: 0.10 M 0 0

Change: -x +x +x

Equilibrium: (0.10 - x) M x x

As the value of $K_{a}$ is very small. So, it is assumed that the compound will dissociate very less. Hence, x << 0.10 M.

And, (0.10 - x) will be approximately equal to 0.10 M.

The expression for $K_{a}$ value is as follows.

$K_{a} = \frac{[Cu(H_{2}O)^{2+}_{6}][H_{3}O^{+}]}{[Cu(H_{2}O)^{2+}_{6}]}\\1.0 \times 10^{-8} = \frac{x \times x}{0.10}\\x = 3.2 \times 10^{-5}$

Hence, $[H_{3}O^{+}] = 3.2 \times 10^{-5}$

Formula to calculate pH is as follows.

$pH = -log [H^{+}]$

Substitute the values into above formula as follows.

$pH = -log [H^{+}]\\= - log (3.2 \times 10^{-5})\\= 4.49$

Thus, we can conclude that the pH of 0.10 M $Cu(NO_{3})_{2}(aq)$ is 4.49.

8 0

3 years ago

How do you think the atomic radii will change as electrons are added to a shell?

kirill115 [55]

Answer:

As electrons are added to the valence shell, an extra proton (i.e fundamental, positively charged nuclear particle) is added to the element's nucleus. As electrons add and Z the atomic number increases 1 by 1, nuclear charge WINS, and electronic radii contract.

Explanation:

Hope this helps you

Crown me as brainliest:)

3 0

3 years ago

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