Explanation:
The given data is as follows.
           = 100 mm Hg or
 = 100 mm Hg or  = 0.13157 atm
 = 0.13157 atm
           =
 =  = (1080 + 273) K = 1357 K
 = (1080 + 273) K = 1357 K
           =
 =  = (1220 + 273) K = 1493 K
 = (1220 + 273) K = 1493 K
           = 600 mm Hg or
 = 600 mm Hg or  = 0.7895 atm
 = 0.7895 atm
           R = 8.314 J/K mol
According to Clasius-Clapeyron equation, 
                    
             ![log(\frac{0.7895}{0.13157}) = \frac{\Delta H_{vap}}{2.303 \times 8.314 J/mol K}[\frac{1}{1357 K} - \frac{1}{1493 K}]](https://tex.z-dn.net/?f=log%28%5Cfrac%7B0.7895%7D%7B0.13157%7D%29%20%3D%20%5Cfrac%7B%5CDelta%20H_%7Bvap%7D%7D%7B2.303%20%5Ctimes%208.314%20J%2Fmol%20K%7D%5B%5Cfrac%7B1%7D%7B1357%20K%7D%20-%20%5Cfrac%7B1%7D%7B1493%20K%7D%5D)
           ![log (6) = \frac{\Delta H_{vap}}{19.147}[\frac{(1493 - 1357) K}{1493 K \times 1357 K}]](https://tex.z-dn.net/?f=log%20%286%29%20%3D%20%5Cfrac%7B%5CDelta%20H_%7Bvap%7D%7D%7B19.147%7D%5B%5Cfrac%7B%281493%20-%201357%29%20K%7D%7B1493%20K%20%5Ctimes%201357%20K%7D%5D)
                 0.77815 = 
                =
 =  J/mol
 J/mol
                                    = 
                                     = 221.9 kJ/mol
Thus, we can conclude that molar heat of vaporization of substance X is 221.9 kJ/mol.
 
 
        
             
        
        
        
Answer:
The second ring in an atom can only hold up to 8 electrons. 
 
        
             
        
        
        
Answer:
See below.
Explanation:
That is because  of the .48. 
85.48 is closer to 85 than 86.
 
        
             
        
        
        
Answer:
Answer: No. An ore is a rock having large amounts of a mineral. Minerals may or may not be commercially useful.