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cestrela7 [59]
3 years ago
12

Which inequality represents "six times a number is less than negative thirty-nine and three-quarters"?

Mathematics
1 answer:
jarptica [38.1K]3 years ago
3 0

Answer:

6*n < - (39 + 3/4)

Step-by-step explanation:

Let's do it in steps:

"Six times a number" can be written as:

6*n

Where n is the "number"

"... is less than negative thirty-nine and three-quarters "

then we have:

6*n < - (39 + 3/4)

This is the inequality we wanted, now we can also solve this for n as:

n < -(39 + 3/4)/6

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Given $dc = 7$, $cb = 8$, $ab = \frac{1}{4}ad$, and $ed = \frac{4}{5}ad$, find $fc$. Express your answer as a decimal.
Pachacha [2.7K]

A ↔ B ↔ C ↔ D ↔ E ↔ F

 \frac{1}{4} AD      8      7      \frac{4}{5} AD   ???

AB + BC + CD = AD   <em>segment addition postulate</em>

\frac{1}{4} AD   +   8   +   7   = AD

\frac{1}{4} AD   +       15        = AD

AD         + 60    = 4AD

                  60    = 3AD

                  20    = AD

AB =  \frac{1}{4} AD    =  \frac{1}{4}(20)    = 5

DE =  \frac{4}{5}AD   =  \frac{4}{5}(5)    = 4

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7   +   4   + EF  = CF

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Answer: 11 + EF

Note: You did not provide any info about EF.  If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.

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