Answer:
Part 4) Right triangle
Part 5) Kite
Step-by-step explanation:
Part 4) What kind of triangle is made by connecting the points A(0, –6), B(3, –6), and C(3, –2)?
Using a graphing tool
see the attached figure N 
The triangle of the figure is not equilateral------> The triangle does not have three equal sides
The triangle of the figure is a right triangle------>The triangle has an angle of 
The triangle of the figure is not isosceles------> The triangle does not have two equal sides
The triangle of the figure is not a right and isosceles
Part 5) What type of quadrilateral is formed by connecting the points
?
Using a graphing tool
see the attached figure N
The figure is not a rhombus------> All sides are not congruent
The figure is not a trapezoid-----> has not parallel sides
The figure is a kite------> Two disjoint pairs of consecutive sides are congruent and the diagonals meet at a right angle
36
Step-by-step explanation:
5x is 15
x is 3
12 times 3 is 36
x = -52 4/17
the full answer in attachments
Hi how do I answer hi how do I answer
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment