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Lelu [443]
3 years ago
6

How do you solve this problem?

Mathematics
2 answers:
Sholpan [36]3 years ago
5 0

Answer:

21. r; 2.83 d; 5.66

22. d; 13.4 c; 42.09

23. r; 5.3 c; 33.30

24. r; 0.49 d; 0.99

Step-by-step explanation:

Hope this helps ;)

Inessa05 [86]3 years ago
5 0

Answer:

21) r; 2.83 d; 5.66     22) d; 13.4 c; 42.09

23) r; 5.3 c; 33.30     24) r; 0.49 d; 0.99

Step-by-step explanation:

it says someone just answered while i was typing so hopefully this is right

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Help please. Due Friday
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5 0
3 years ago
Rita has $b. Sharron has $11.50 less than Rita.
taurus [48]

Answer:

h = b - 11.50

Step-by-step explanation:

Sharron(h) has 11.50 less than Rita(b)

h = b - 11.50

3 0
2 years ago
If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se
notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or higher?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or higher

5 0
3 years ago
Help please?
Gennadij [26K]

Answer:

Step-by-step explanation:

with the largest measure

8 0
3 years ago
Read 2 more answers
An occupational safety officer for a large company is conducting a study to investigate back problems in office workers who use
Oduvanchick [21]

Answer:

с. A matched pairs t-interval for a mean difference.

Step-by-step explanation:

With the sample, we will have possession of the sample mean and of the sample standard deviation, which means that the t-distribution will be used.

We want to find the mean number of back problems for each sample, and estimate the difference. Since the groups are similar, with only the positions in which they work being different, we have matched pairs. So the correct answer is given by option c.

7 0
3 years ago
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