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const2013 [10]
3 years ago
9

Someone help with this pls

Chemistry
1 answer:
Sauron [17]3 years ago
7 0

Answer:

12 B

13

0.00100176

Explanation:

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A certain substance X has a normal boiling point of 117.8°C and a molal boiling point elevation constant =Kb·0.63°C·kgmol−1. A s
OlgaM077 [116]

Answer:

42.8 g was the mass of dissolved urea.

Explanation:

Boiling point elevation to solve this:

ΔT = Kb . m

where ΔT → Boiling T° of solution - Boiling T° of pure solvent

Let's replace the data given:

118.3°C - 117.8°C = 0.63°C/m . m

0.5°C / 0.63 m/°C = m → 0.793 mol/kg

Mass of solvent → 900 g → g to kg → 900 g . 1kg/1000 = 0.9 kg

Molality . kg = moles → 0.793 mol/kg . 0.9 kg = 0.714 mol

These are the moles of urea we used. Let's determine the mass dissolved.

0.714 mol . 60 g /1mol = 42.8 g

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4 years ago
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Answer:

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Explanation:

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3 years ago
Please help me this is due by midnight!!
mamaluj [8]

Answer:

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3 years ago
How would you write 2,200 in picometers? Or would the number just be 2,200 picometers? PLEASE HELP!
Anestetic [448]
I believe your answer is 2200000000000000. I hope this can help you :)
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4 years ago
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