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Musya8 [376]
3 years ago
15

Sulfur is to the immediate right of phosphorus in the same row in the periodic table. Which of the following statements compares

the radius and number of protons of nitrogen and oxygen atoms? Sulfur has a smaller radius and one more proton than phosphorous. Sulfur has a smaller radius and one proton less than phosphorous. Sulfur has a larger radius and one proton less than phosphorous. Sulfur has a larger radius and one proton more than phosphorous.
Chemistry
1 answer:
suter [353]3 years ago
7 0
The correct answer is that sulfur has a smaller radius and one proton more than phosphorus.

This is because if sulfur is to the immediate right of phosphorus, it must have one more proton due to the fact that the periodic table is arranged by increasing atomic number (number of protons) of its elements.

The atomic radius of elements decreases across a period because the greater number of protons has an increased “pull” on the electrons, pulling them in closer to the nucleus and thus making the atomic radius smaller.

Hope this helps!
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What is the molarity of a 27.0% (v/v) aqueous ethanol solution? the density of ethanol (c2h6o, molar mass 46.07 g/mol) is 0.790
RoseWind [281]
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         calculation
convert  27%(v/v) to  fraction  = 27ml/100 ml

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6 0
3 years ago
Read 2 more answers
The most common copper ore used in the production of copper is chalcopyrite. If a chalcopyrite ore contains 55.0% CuFeS2, how ma
sattari [20]
Answer is: 315,29 grams of copper ore.
m(<span>chalcopyrite) = ?
</span>ω(CuFeS₂) = 55,0 % = 0,55.
<span>m(Cu) = 60,0 g.
mass percentage of copper in </span>CuFeS₂:
ω(Cu) = Ar(Cu) ÷ Mr(CuFeS₂).
ω(Cu) = 63,55 ÷ 183,4.
ω(Cu) = 0,346 = 34,6 %.
mass percentage of copper in chalcopyrite:
ω(Cu) : ω₁(Cu) = 100% : ω(CuFeS₂).
ω₁(Cu) = 19,03 % = 0,1903.
m(chalcopyrite) = 60,0 g ÷ 0,1903.
m(chalcopyrite) = 315,29 g.

8 0
3 years ago
Read 2 more answers
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