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GuDViN [60]
3 years ago
10

Calculate the [H+] for a solution with a pOH of 4.75

Chemistry
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

Explanation:

A. 1.3 x 10-10 M

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A sample of neon occupies a volume of 478 mL at STP. What will be the volume of the neon when the pressure is reduced to 93.3 kP
Andre45 [30]

The volume of neon when the pressure is reduced to 93.3 kPa is 519 mL.

Explanation:

The kinetic theory of gases is mostly based on Boyle's law. From the Boyle's law, the pressure experienced by any gas molecules is inversely proportional to volume of the gas molecules. Also this inverse relation is obeyed if and only if the number of moles and temperature of the gas molecules remained constant.

So,P=\frac{1}{V}

So if there is a change in pressure then there will be inverse change in volume. That means if there is decrease in the pressure of gas molecules then there will be increase in the volume and vice versa.

So the Boyle's law is combined as P_{1} V_{1} = P_{2} V_{2}

As here the initial pressure or P_{1} is 1 atm or 101.3 kPa and the initial volume is 478 mL. Similarly, the final pressure is 93.3 kPa and the final volume will be

101.3*10^{3}*478*10^{-3}  = 93.3*10^{3} * V_{2}

V_{2} = 519 mL

So, the volume of neon when the pressure is reduced to 93.3 kPa is 519 mL.

5 0
3 years ago
All minerals on the mohs hardness scale are hard enough to scratch a piece of glass is it true or false
11Alexandr11 [23.1K]
The answer is false
8 0
3 years ago
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In a chemical reaction, which are the most likely products of these reactants 4Fe+302
Cerrena [4.2K]

2Fe2O3, reason is when we add 4Fe + 3O2, we get the same answer, but in a different form.

8 0
3 years ago
What is the mass of solute in a 500 mL solution of 0.200 M
Fofino [41]

16.4 grams is the mass of solute in a 500 mL solution of 0.200 M .

sodium phosphate

Explanation:

Given data about sodium phosphate

atomic mass of Na3PO4 = 164 grams/mole

volume of the solution = 500 ml or 0.5 litres

molarity of sodium phosphate solution = 0.200 M

The formula for molarity will be used here to know the mass dissolved in the given volume of the solution:

The formula is

molarity = \frac{number of moles of solute}{volume in litres}

    putting the values in the equation, we get

molarity x volume = number of moles

0.200 X 0.5= number of  moles

number of moles = 0.1 moles

Atomic mass x number of moles = mass

putting the values in the above equation

164 x 0.1 = 16.4 grams

16.4 grams of sodium phosphate is present in 0.5 L of the solution to make a 0.2 M solution.

8 0
3 years ago
Classify the following substances as acids or bases.
ella [17]
A=acid
B=it say neither it say it’s alkaline
C=acid
D= it say neither it say it’s alkaline
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