Answer:
D)
Explanation:
This seems like a weird question
Water is held together by covalent bonds. The amount of energy required to break these bonds so that water would split into it's respective ions is pretty high. The chances that any one of the molecules floating in 1L of water get enough energy to spontaneously burst into it's ions is slim to none.
So, D) seems like the most likely answer
Answer:
The voltage delivered by a primary battery is unrelated to its size.
Answer:
because it showed how the electron could orbit the nucleus without falling into it.
Answer:
5
Explanation:
We can obtain the value of x by doing the following:
Mass of hydrated salt (CuSO4.xH2O) = 1.50g
Mass of anhydrous salt (CuSO4) = 0.96g
Mass of water molecule(xH2O) = 1.50 — 0.96 = 0.54g
Molar Mass of CuSO4.xH2O = 63.5 + 32 + (16x4) + x(2 +16) = 63.5 + 32 + 64 + 18x = 159.5 + 18x
Mass of water(xH2O) molecules in the hydrate salt is given by:
xH2O/CuSO4.xH2O = 0.54/1.5
18x/(159.5 + 18x) = 0.36
Cross multiply to express in linear form
18x = 0.36 (159.5 + 18x)
18x = 57.42 + 6.48x
Collect like terms
18x — 6.48x = 57.42
11.52x = 57.42
Divide both side by 11.52
x = 57.42/11.52
x = 5
Therefore, the unknown integer x is 5 and the formula for the hydrated salt is CuSO4.5H2O
Answer : The mass of helium gas added must be 12.48 grams.
Explanation : Given,
Mass of helium (He) gas = 6.24 g
Molar mass of helium = 4 g/mole
First we have to calculate the moles of helium gas.
Now we have to calculate the moles of helium gas at doubled volume.
According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,
or,
where,
= initial volume of gas = V
= final volume of gas = 2V
= initial moles of gas = 1.56 mole
= final moles of gas = ?
Now we put all the given values in this formula, we get
Now we have to calculate the mass of helium gas at doubled volume.
Therefore, the mass of helium gas added must be 12.48 grams.
