One mole of water weighs 18 grams. H₂O is composed of 2H= 2 and 1 0=16 adding gives you 18. number of moles= mass/ Relative Molecular Mass
Therefore, mass= Relative Molecular Mass×number of moles
= 18×5 moles
= 90 grams
Answer:
6.5 moles of Oxygen are required
Explanation:
Based on the reaction:
CH3OH + 1/2 O2 → CH2O + H2O
1 mole of methanol reacts with 1/2 moles O2 to produce 1 mole of formaldehyde and 1 mole of water.
Thus, to produe 13 moles of formaldehyde, CH2O, are needed:
13 moles CH2O * (1/2mol O2 / 1mol CH2O) =
<h3>6.5 moles of Oxygen are required</h3>
Answer:
0.752 J/g*K
Explanation:
The heat lost by the alloy (which is negative) must be equal to the heat gained by the water and the coffee cup:
-Qa = Qw + Qc
-ma*ca*ΔTa = mw*cw*ΔTw + C*ΔTc
Where, m is the mass, c is the specific heat capacity, C is the heat capacity of the coffee cup, ΔT is the change in temperature, a represents the alloy, and w the water.
The coffee cup has initial temperature equal to the water, then:
-30.5*ca*(31.1 - 95.0) = 49.3*4.184*(31.1 - 24.3) + 9.2*(31.1 - 24.3)
1948.95ca = 1465.20
ca = 0.752 J/g*K
