Answer:
Quadrilateral ABCD is not a square. The product of slopes of its diagonals is not -1.
Step-by-step explanation:
Point A is (-4,6)
Point B is (-12,-12)
Point C is (6,-18)
Point D is (13,-1)
Given that the diagonals of a square are perpendicular to each other;
We know that the product of slopes of two perpendicular lines is -1.
So, slope(m) of AC × slope(m) of BD should be equal to -1.
Slope of AC = (Change in y-axis) ÷ (Change in x-axis) = (-18 - 6) ÷ (6 - -4) = -24/10 = -2.4
Slope of BD = (Change in y-axis) ÷ (Change in x-axis) = (-1 - -12) ÷ (13 - -12) = 11/25 = 0.44
The product of slope of AC and slope of BD = -2.4 × 0.44 = -1.056
Since the product of slope of AC and slope of BD is not -1 hence AC is not perpendicular to BD thus quadrilateral ABCD is not a square.
Answer:
$7.79 per pair of gloves
Step-by-step explanation:
divide
31.16÷ 4 = 7.79
Answer:
the answer would be y=2x+4
Step-by-step explanation:
Answer:
all i know is A and it is -1,-2
Step-by-step explanation:
<u>Answer:</u>
The correct answer option is: 
.
<u>Step-by-step explanation:</u>
We know that the 
term 
for an arithmetic sequence is given by:
where 
is the number of the position of the term.
We are supposed to find the first four terms of the sequence so we will substitute the values of from 1 to 4 in the given formula to get:
1st term:
2nd term:
3rd term:
4th term:
