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3 years ago

Energy in the form of heat flows from _ to _ until both temperatures are the ___.

Physics

2 answers:

Andreyy893 years ago

4 0

Answers:

The answer are Hot, Cold, and same

ohaa [14]3 years ago

3 0

The answer is the answer is hot ,cold and same

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Air rushing over the wings of high-performance race cars generates unwanted horizontal air resistance but also causes a vertical

Nookie1986 [14]

Answer:

10.897 m/s²

Explanation:

$f_s$ = Slipping force

$F_d$ = Downforce = 3620 N

$\mu$ = Coefficient of static friction = 0.843

m = Mass of car = 678 kg

$f_h$ = Horizontal force = 1270 N

g = Acceleration due to gravity = 9.81 m/s²

$a=\frac{f_s-f_h}{m}\\\Rightarrow a=\frac{\mu(F_D+mg)-f_h}{m}\\\Rightarrow a=\frac{0.843(3620+678\times 9.81)-1270}{678}\\\Rightarrow a=10.897\ m/s^2$

Hence, magnitude of the maximum acceleration is 10.897 m/s²

5 0

3 years ago

Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19

sergejj [24]

The distance between the charges is 13.86 X 10⁴m

<u>Explanation:</u>

Given:

Force, F = 1.2N

Charge, q₁ = 1.602 X 10⁻¹⁹ C

k = 8.987 X 10⁹ Nm²/C²

Distance, d = ?

According to Coulomb's law:

$F = k\frac{q_1q_2}{r^2} \\\\$

Substituting the value in the formula we get:

$1.2 = 8.987X 10^9 X\frac{1.602 X 10^-^1^9 X 1.602 X 10^1^9}{r^2} \\\\1.2 = \frac{23.06 X 10^9}{r^2} \\\\r^2 = 19.22 X 10^9\\\\r = 13.86 X 10^4m$

Therefore, the distance between the charges is 13.86 X 10⁴m

5 0

3 years ago

Even if it is wrong, why is a hypothesis important?

Setler79 [48]

So you can have a understanding of what you are doing and figure out your overall goal

8 0

2 years ago

Two students, standing on skateboards, are initially at rest, when they give each other a shove! After the shove, one student (7

Elden [556K]

Answer:

The other student (59kg) moves right at 7.44 m/s

Explanation:

Given;

mass of the first student, m₁ = 77kg

mass of the second student, m₂ = 59kg

initial velocity of the first student, u₁ = 0

initial velocity of the second student, u₂ = 0

final velocity of the first student, v₁ = 5.7 m/s left

final velocity of the second student, v₂ = ? right

Apply the principle of conservation of linear momentum;

Total momentum before collision = Total momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(77 x 0) + (59 x 0) = (-77 x 5.7) + (59 x v₂)

0 = - 438.9 + 59v₂

59v₂ = 438.9

v₂ = 438.9 / 59

v₂ = 7.44 m/s to the right

Therefore, the other student (59kg) moves right at 7.44 m/s

6 0

3 years ago

Two 1.9 kg masses are 1.1 m apart (center to center) on a frictionless table. Each has + 9.6 μC of charge.

Anni [7]

Answer:

F= 0.6 N

Explanation:

Fe(electrical force)= $k q1q2/r^2$

$k=9*10^9\\q1=-9.6 *10^-6 C\\q2= -9.6*10^-6 C\\r= 1.1m$

So,

$F=\frac{9*10^9*-9.6 *10^-6 C* -9.6*10^-6 C}{1.1^2}$

$F= 0.6 N$

5 0

3 years ago

Energy in the form of heat flows from ___ to ___ until both temperatures are the ___.

Energy in the form of heat flows from _ to _ until both temperatures are the ___.