Energy in the form of heat flows from ___ to ___ until both temperatures are the __

a college student rests a backpack upon his shoulder. the pack is suspended motionless by one strap from one shoulder.

Minchanka [31]

The student's shoulder supports the weight of the bag.

<h3>What is the free body diagram?</h3>

Free-body diagrams are utilized to display the relative direction and strength of all forces that are being applied to an item in a certain scenario. A unique illustration of the geometric diagrams that were covered in a previous lesson is the free-body diagram. We will make use of these graphics throughout the entire study of physics.

A university student is carrying a backpack. One strap is hanging the rucksack immobile from one shoulder.

The weight of the backpack is balanced by the shoulder of the student.

The free-body diagram is attached below.

More about the free body diagram link is given below.

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4 0

1 year ago

In what year will there be 8 billion people in the world? <br> 2020 <br> 2022 <br> 2024 <br> 2030

Morgarella [4.7K]

Answer:

2030

Explanation:

6 0

2 years ago

Read 2 more answers

An 18g bullet is shot vertically into a 10kg block. The block lifts upward 9mm. The bullet penetrates the block in a time interv

stealth61 [152]

Answer:

The initial kinetic energy of the bullet is closest to 491.87 J

Explanation:

Given;

mass of bullet, m₁ = 18g = 0.018kg

mass of block, m₂ = 10kg

height moved by the block, h = 9 mm = 0.009 m

time taken for the bullet to travel through the block, t = 0.001s

let the initial velocity of the bullet = v₁

let the final velocity of the bullet = v₂

Apply the principle of conservation of linear momentum;

initial momentum = final momentum

0.018v₁ = v₂(0.018 + 10)

0.018v₁ = 10.018v₂ -----equation (1)

Apply the law of conservation of energy when the bullet lifts the block through 9mm

mgh = ¹/₂mv₂²

gh = ¹/₂v₂²

v₂² = 2gh

v₂ = √2gh

v₂ = √(2 x 9.8 x 0.009)

v₂ = 0.42 m/s

Substitute in v₂ in equation 1, to determine the initial velocity of the bullet;

0.018v₁ = 10.018v₂

0.018v₁ = 10.018(0.42)

0.018v₁ = 4.208

v₁ = 4.208 / 0.018

v₁ = 233.78 m/s

Now, determine the initial kinetic energy of the bullet;

K.E₁ = ¹/₂m₁v₁²

K.E₁ = ¹/₂(0.018)(233.78)²

K.E₁ = 491.87 J

Therefore, the initial kinetic energy of the bullet is closest to 491.87 J

6 0

3 years ago

A diffusion couple, made by welding a thin onecentimeter square slab of pure metal A to a similar slab of pure metal B, was give

bezimeni [28]

Answer:

The value is $H = 18*10^{2} \ Atom / sec$

Explanation:

From the question we are told that

The atom fraction of metal A at point G is $A = 0.30 \ m$

The atom fraction of metal A at a distance 5000nm from G is $A_2 = 0.35$

The number of atoms per $m^3$ is $N_h = 9 * 10^{28}$

The diffusion coefficient is $D = 2* 10^{-14 } m^2/s$

Generally of the concentration of atoms of metal A at G is

$N_A = A * N_h$

=> $N_A = 0.3 * 9 * 10^{28}$

=> $N_A = 2.7 * 10^{28} 2.7 atoms/m^3$

Generally of the concentration of atoms of metal A at a distance 5000nm from G is

$D = 0.35 *9 * 10^{28}$

=> $D = 3.15 * 10^{28} \ atoms / m^3$

The concentration gradient is mathematically represented as

$\frac{dN_A}{dx} = \frac{(3.15 - 2.7) * 10^{28} }{5000nm - 0 }$

=> $\frac{dN_A}{dx} = \frac{(3.15 - 2.7) * 10^{28} }{[5000 *10^{-9}] - 0 }$

=> $\frac{dN_A}{dx} = 9 * 10^{20} / m^4$

Generally the flux of the atoms per unit area according to Fick's Law is mathematically represented as

$J = -D* \frac{d N_A}{dx}$

=> $J = -2* 10^{-14 * 9 * 10^{20}$

=> $J = 18*10^{6}\ atoms\ crossing\ /m^2 s$

Generally if the cross-section area is $a = 1 cm^2 = 10^{-4} \ m^2$

Generally the number of atom crossing the above area per second is mathematically is

$H = 18*10^{6} * 10^{-4}$

=> $H = 18*10^{2} \ Atom / sec$

7 0

3 years ago

A 60kg man jumps off a 30 foot building. Assuming he falls from rest and there is negligible air resistance, how long will it ta

Dmitriy789 [7]

Answer:

1.37 seconds before.... splat !

Explanation:

y = y0 + v0 t + 1/2 a t^2 y0 = 30 y = 0

v0 = 0 ( from rest)

a = - 32.2 ft/s^2

0 = 30 - 1/2 * 32.2 * t^2

t=1.366 seconds <u> Note that mass is irrelevant.</u>

5 0

1 year ago

Energy in the form of heat flows from ___ to ___ until both temperatures are the ___.

Energy in the form of heat flows from _ to _ until both temperatures are the ___.