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Vedmedyk [2.9K]
3 years ago
10

It’s a Gas!

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
8 0
6.) 1
7.) 1
8.) 4
9.)4
10.) 4
11.) 4

I am pretty sure this is the answer
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How much heat is absorbed by a 112.5 g sample of water when it is heated from 12.5 °C to 9°C? (Specific heat capacity of water i
Oduvanchick [21]

Answer:

–1647.45 J

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 112.5 g

Initial temperature (T₁) = 12.5 °C

Final temperature (T₂) = 9°C

Specific heat capacity (C) = 4.184 J/g°C

Heat (Q) absorbed =?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T₁) = 12.5 °C

Final temperature (T₂) = 9°C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 9 – 12.5

ΔT = –3.5 °C

Finally, we shall determine the heat absorbed. This can be obtained as follow:

Mass (M) = 112.5 g

Change in temperature (ΔT) = –3.5 °C

Specific heat capacity (C) = 4.184 J/g°C

Heat (Q) absorbed =?

Q = MCΔT

Q = 112.5 × 4.184 × –3.5

Q = –1647.45 J

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3 years ago
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