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3 years ago

Select the number of valence electrons for fluorine.

Chemistry

2 answers:

Arte-miy333 [17]3 years ago

6 0

Seven valence electrons is your answer

solniwko [45]3 years ago

6 0

Answer : The number of valence electrons in fluorine are, seven.

Explanation :

As we know that the fluorine is a non-metal element that belongs to the group 17 and period 2. The symbol of fluorine element is, (F) and the atomic number of fluorine is, 9.

The electronic configuration of fluorine is, $1s^22s^22p^5$

Electronic configuration : It is defined as the distribution of electrons of an atom in an atomic orbitals.

From the electronic configuration, we conclude that the number of valence electrons present in fluorine is, seven (7).

Hence, the number of valence electrons in fluorine are, seven.

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A forest has a stable population of approximately 100 great horned owls. The owls nest in hollow trees, eat small animals, and h

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Since electrons ___ each other, electrons pairs will be as _____ apart as possible

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We have to answer based on basic concept on electron.

The correct answer is: Since electrons repel each other, electrons pairs will be as far apart as possible.

We know, electrons are negatively charged particles and negatively charged particles repel to each other.

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2 years ago

When a student mixes 50 mL of 1.0 M HCl and 50 mL of 1.0 M NaOH in a coffee-cup calorimeter, the temperature of the resultant so

zmey [24]

Answer: 54.4 kJ/mol

Explanation:

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=1.0M\times 0.05=0.05mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=1.0\times 0.05L=0.05mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.05 mole of HCl neutralizes by 0.05 mole of NaOH

Thus, the number of neutralized moles = 0.05 mole

Now we have to calculate the mass of water:

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $50ml+50ml=100ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 100ml=100g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 100 g

$T_{final}$ = final temperature of water = $27.5^0C$

$T_{initial}$ = initial temperature of metal = $21.0^0C$

Now put all the given values in the above formula, we get:

$q=100g\times 4.18J/g^oC\times (27.5-21.0)^0C$

$q=2719.6J=2.72kJ$

Thus, the heat released during the neutralization = 2.72 KJ

Now we have to calculate the enthalpy of neutralization per mole of $HCl$ :

0.05 moles of $HCl$ releases heat = 2.72 KJ

1 mole of $HCl$ releases heat = $\frac{2.72}{0.05}\times 1=54.4KJ$

Thus the enthalpy change for the reaction in kJ per mol of HCl is 54.4 kJ

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2 years ago

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3 years ago