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tensa zangetsu [6.8K]
3 years ago
13

Select the number of valence electrons for fluorine.

Chemistry
2 answers:
Arte-miy333 [17]3 years ago
6 0
Seven valence electrons is your answer
solniwko [45]3 years ago
6 0

Answer : The number of valence electrons in fluorine are, seven.

Explanation :

As we know that the fluorine is a non-metal element that belongs to the group 17 and period 2. The symbol of fluorine element is, (F) and the atomic number of fluorine is, 9.

The electronic configuration of fluorine is, 1s^22s^22p^5

Electronic configuration : It is defined as the distribution of electrons of an atom in an atomic orbitals.

From the electronic configuration, we conclude that the number of valence electrons present in fluorine is, seven (7).

Hence, the number of valence electrons in fluorine are, seven.

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Using the balanced equation below,
Zielflug [23.3K]

Answer:

Mass = 6.538 g

Explanation:

Given data:

Mass of zinc hydroxide produced = 9.65 g

Mass of zinc required = ?

Solution:

Chemical equation:

Zn + 2MnO₂ + H₂O      →      Zn(OH)₂ + Mn₂O₃

Number of moles of zinc hydroxide:

Number of moles = mass/molar mass

Number of moles = 9.65 g/ 99.42 g/mol

Number of moles = 0.1 mol

now we will compare the moles of zinc and zinc hydroxide,

                  Zn(OH)₂           :          Zn

                       1                  :          1

                    0.1                  :         0.1

Mass of zinc required:

Mass = number of moles × molar mass

Mass = 0.1 mol × 65.38 g/mol

Mass = 6.538 g

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