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Yanka [14]
3 years ago
5

What's Meso compounds? Please explain it to me with an appropriate example. I'll mark you as Brainliest ​

Chemistry
1 answer:
slamgirl [31]3 years ago
4 0

Answer:

this can be explained as a non optically active member of a set of stereoisomer, at least two of which are optically active

Explanation:

this means that despite containing two or sterogeonic center the molecules are not chiral

example:

the example above shows at least two choral center and internal mirror plane

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If you use 65.34 g of Al2S3, how many grams of AICl3 can be produced?​
Doss [256]

Answer:

sorry po

indi ko po maintindihan

6 0
3 years ago
What unknown quantity can be calculated after performing a titration? a. volume c. mass b. concentration d. density
sertanlavr [38]
C & B are switched so I'm not sure if that was a typo or not, but the answer is concentration!
3 0
3 years ago
The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure
Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature T_1

P_2 = vapor pressure at temperature T_2

\Delta H_{vap} = Enthalpy of vaporization  

R = Gas constant = 8.314 J/mol K

1) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =363 K

T_2 = final temperature =373 K

P_2=1 atm, P_1=?

Putting values in above equation, we get:

\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]

P_1=0.69671 atm \approx 0.6970 atm

The vapor pressure at temperature 363 K is 0.6970 atm

2) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =373 K

T_2 = final temperature =383 K

P_1=1 atm, P_2?

Putting values in above equation, we get:

\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]

P_2=1.4084 atm \approx 1.410 atm

The vapor pressure at 383 K is 1.410 atm

8 0
3 years ago
Plz answer this question.....I know the answer for this question but I want to know the explanation plz plz plz I want to know t
vlabodo [156]

The compound C_{3}H_{4} will have a triple bond.

Explanation:

A compound which consists of carbon and hydrogen atoms is known as a hydrocarbon.

Alkanes, alkenes and alkynes are all hydrocarbons.

  • General chemical formula of an alkane is C_{n}H_{2n+2}. In an alkane molecule, all the atoms will be bonded through single bonds.

For example, C_{3}H_{8} is propane.

  • General chemical formula of an alkene is C_{n}H_{2n}. An alkene molecule will have atleast one double bond between two carbon atoms.

For example, C_{2}H_{4} is ethene.

  • General chemical formula of an alkyne is C_{n}H_{2n-2}. An alkyne will have atleast one triple bond between two carbon atoms.

For example, C_{3}H_{4} is propyne.

Thus, we can conclude that out of the given options C_{3}H_{4} will have a triple bond.

8 0
3 years ago
Determine how many millilitres of a 4.25 M HCl solution are needed to react completely with 8.75 g CaCO3?
Helen [10]

Answer:

41 mL

Explanation:

Given data:

Milliliter of HCl required = ?

Molarity of HCl solution = 4.25 M

Mass of CaCO₃ = 8.75 g

Solution:

Chemical equation:

2HCl + CaCO₃      →    CaCl₂ + CO₂ + H₂O

Number of moles of CaCO₃:

Number of moles = mass/molar mass

Number of moles = 8.75 g / 100.1 g/mol

Number of moles = 0.087 g /mol

Now we will compare the moles of  CaCO₃ with HCl.

                      CaCO₃         :          HCl

                          1               :            2

                      0.087           :         2/1×0.087 = 0.174 mol

Volume of HCl:

Molarity = number of moles / volume in L

4.25 M = 0.174 mol / volume in L

Volume in L = 0.174 mol /4.25 M

Volume in L = 0.041 L

Volume in mL:

0.041 L×1000 mL/ 1L

41 mL

8 0
3 years ago
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