A pure gold bar is made up of only particles. <br><br>A.nickel<br>B.copper <br>C.god<br>D.gold

(( PLEASE HELP QUICK ))Which expression can be used to calculate the ratio of the rate of effusion of gas A to the rate of effus

borishaifa [10]

Answer:

The square root of the molar mass of B ÷ the square root of the molar mass of A

Explanation:

Graham’s Law applies to the effusion of gases:

The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

$r \propto \dfrac{1}{\sqrt{M}}$

If you have two gases A and B, the ratio of their rates of effusion is

$\dfrac{r_{\text{A}}}{r_{\text{B}}} = \sqrt{\dfrac{M_{\text{B}}}{M_{\text{A}}}}$

3 0

2 years ago

What is the new pressure if the temperature outside is 296k and his weight causes the tire's volume to drop to 2.0 liters

sukhopar [10]

Question:

At standard temperature and pressure, the volume of a tire is 3.5L. What is the new pressure if the temperature outside is 296k and its weight causes the volume of the gas is 2.0 L?

Answer:

The new pressure is: 1.896 atm

Explanation:

At standard temperature and pressure, we have:

$P_1 = 1atm$

$T_1 = 273.15k$

$V_1 = 3.5L$

Outside, we have:

$T_2 = 296k$

$V_2 = 2.0L$

Required

Determine the new pressure

Using combined gas law, we have:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

This gives:

$\frac{1 * 3.5}{273.15} =\frac{P_2*2.0}{296}$

Solve for $P_2$

$P_2 = \frac{296 * 1 * 3.5}{273.15*2.0}$

$P_2 = \frac{1036}{546.30}$

$P_2 \approx 1.896 atm$

7 0

2 years ago

The elements X and Y combine in different ratios to form four different types of compounds: XY, XY2, XY3, and XY4. Consider that

Law Incorporation [45]

Answer:

Ratios in order of increasing value ; The ratio of the mass ratio of Y to X in XY2 to the mass ratio of Y to X in XY, The ratio of the mass ratio of Y to X in XY3 to the mass ratio of Y to X in XY, The ratio of the mass ratio of Y to X in XY4 to the mass ratio of Y to X in XY

1) Mass ratio = 3

2) Mass ratio = 2

3) Mass ratio = 4

Explanation:

The detailed and step by step calculation is shown in the attachment.

3 0

2 years ago

Balance the following redox equation using the smallest integers possible and select the correct coefficient for the hydrogen su

goldfiish [28.3K]

Answer:

Coefficient of $HSO_{3}^{-}$ is 5

Explanation:

Oxidation: $MnO_{4}^{-}(aq)\rightarrow Mn^{2+}(aq)$

Balance O and H in acidic medium: $MnO_{4}^{-}(aq)+8H^{+}(aq)\rightarrow Mn^{2+}(aq)+4H_{2}O(l)$
Balance charge : $MnO_{4}^{-}(aq)+8H^{+}(aq)+5e^{-}\rightarrow Mn^{2+}(aq)+4H_{2}O(l)$ .............(1)

Reduction: $HSO_{3}^{-}\rightarrow SO_{4}^{2-}$

Balance O and H in acidic medium : $HSO_{3}^{-}(aq)+H_{2}O(l)\rightarrow SO_{4}^{2-}(aq)+3H^{+}(aq)$
Balance charge : $HSO_{3}^{-}(aq)+H_{2}O(l)-2e^{-}\rightarrow SO_{4}^{2-}(aq)+3H^{+}(aq)$ ..............(2)