Hey boys, say "make me" I dare you ;)
2 answers:
You might be interested in
Answer:
Hello your question has some missing parts attached below is the missing part
A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below.
answer : speed at x = 5 m = 3.35 m/s
speed at x = 15m = 5.12 m/s
Explanation:
initial speed( x = 0 ) = 2.5 m/s
speed at x = 5.00 m = ?
speed at x = 15 m = ?
Determine speed at x = 5 m
First we will apply the expression for work-energy theorem
w = ----- ( 1 )
where : w = 7.50J, = 2.5m/s , m = 3.0 kg ( in the expression of work )
input values into equation 1
7.50 = 1/2 (3 ) ( v^2 - 2.5^2 )
7.50 = 3/2 ( v^2 - 6.25 )
5 j/kg = v^2 - 6.25
∴ v = √11.25 = 3.35 m/s
Determine speed at X = 15
first we will determine the work done form x = 5 to x = 15
W = 7.5J + 15J + 7.5J = 30J, = 2.5m/s , m = 3.0 kg
w = --- ( 2 )
equation2 becomes
30J = 1/2 ( 3 ) ( v^2 - 6.25 )
30J = 3/2 ( V^2 - 6.25 )
20 J/kg = v^2 - 6.25
v = √26.25 = 5.12 m/s
In a circuit having 2 lamps are connected in parallel to a battery
then the two lamps will be having the same potential as the battery
i.e
As per Ohm's law,
and
In other words, each lamp's current is inversely related to its individual resistance. We only know the current in one of the bulbs in this specific instance. We would therefore need further information in order to calculate the current in the other light. Therefore, there isn't enough data to make a statement.
Under the assumption that all physical parameters, including temperature, remain constant, Ohm's law asserts that "the voltage across a conductor is directly proportional to the current flowing through it".
Learn more about Ohm's law here
#SPJ4