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lakkis [162]
3 years ago
7

Why are some consolation visible to New York State observers at midnight during April , but not visible at midnight during Octob

er
Physics
1 answer:
Svetach [21]3 years ago
3 0
"Midnight" means looking away from the Sun. But in 6 months from April to October the earth goes halfway around the Sun. So midnight in April and midnight in October are exactly opposite directions.
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A wooden block of mass M resting on a frictionless, horizontal surface is attached to a rigid rod of length ℓ and of negligible
mr Goodwill [35]

Answer:

a)

mv l

b)

\frac{M }{(M + m)}

Explanation:

Complete question statement is as follows :

A wooden block of mass M resting on a friction less, horizontal surface is attached to a rigid rod of length ℓ and of negligible mass. The rod is pivoted at the other end. A bullet of mass m traveling parallel to the horizontal surface and perpendicular to the rod with speed v hits the block and becomes embedded in it.

(a) What is the angular momentum of the bullet–block system about a vertical axis through the pivot? (Use any variable or symbol stated above as necessary.)

(b) What fraction of the original kinetic energy of the bullet is converted into internal energy in the system during the collision? (Use any variable or symbol stated above as necessary.)

a)

m = mass of the bullet

v = velocity of the bullet before collision

r = distance of the line of motion of bullet from pivot = l

L = Angular momentum of the bullet-block system

Angular momentum of the bullet-block system is given as

L = m v r

L = mv l

b)

V = final velocity of bullet block combination

Using conservation of momentum

Angular momentum of bullet block combination = Angular momentum of bullet

(M + m) V l = m v l\\V =\frac{mv}{(M + m)}

K_{o} = Initial kinetic energy of the bullet

Initial kinetic energy of the bullet is given as

K_{o} = (0.5) m v^{2}

K_{f} = Final kinetic energy of bullet block combination

Final kinetic energy of bullet block combination is given as

K_{f} = (0.5) (M + m) V^{2}

Fraction of original kinetic energylost is given as

Fraction = \frac{(K_{o} - K_{f})}{K_{o}} = \frac{((0.5) m v^{2} - (0.5) (M + m) V^{2})}{(0.5) m v^{2}}

Fraction = \frac{(m v^{2} - (M + m) (\frac{mv}{(M + m)})^{2})}{m v^{2}} = \frac{(Mm v^{2} + m^{2} v^{2} - m^{2} v^{2})}{(M + m) m v^{2}}

Fraction = \frac{(Mm v^{2} + m^{2} v^{2} - m^{2} v^{2})}{(M + m) m v^{2}}\\ \frac{M }{(M + m)}

6 0
3 years ago
An airplane flies in a loop (a circular path in a vertical plane) of radius 160 m . The pilot's head always points toward the ce
notka56 [123]

Answer:

a) 39.6 m/s b) 4123 N

Explanation:

a) At the top of the loop, all of the forces point downwards (force of gravity and normal force).

Fnet=ma

ma=m(v^2/R) (centripetal acceleration)

mg=m(v^2/R)

m cancels out (this is why pilot feels weightless) so,

g=(v^2/R)

9.8 m/s^2 = v^2/160 m

v^2=1568 m^2/s^2

v=39.6 m/s

b) At the bottom of the loop, the normal force and the force of gravity point in opposite directions. The normal force is the weight felt.

Convert 300 km/hr to m/s

300 km/hr=83.3 m/s

Convert pilot's weight into mass:

760 N = 77.55 kg

Fnet=ma

n-mg=m(v^2/R)

n=(77.55 kg)(((83.3 m/s)^2)/160 m)+(77.55 kg)(9.8 m/s^2)

n=3363.2 N+760 N=4123 N

5 0
2 years ago
Which of the following is NOT proof of a chemical change
Blababa [14]

Answer:

E

Explanation:

all are proof Eeeeeeeeeee

4 0
3 years ago
Read 2 more answers
The chemical formula for sodium fluoride is A) Na7F B) NaF C) NaF2 D) NaF7
ikadub [295]
The correct answer would be the letter B.) NaF this attracts opposite charges. The final formula of sodium fluoride would be NaF it’s <span>compound is formed by the complete transfer of electrons from a metal to a nonmetal.</span>
8 0
3 years ago
Read 2 more answers
What are three examples of constructive forces
Olin [163]
The three main constructive forces are crustal deformation, volcanic eruptions, and deposition of sediment.
5 0
2 years ago
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