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kenny6666 [7]
2 years ago
9

F = xi+yj+2zk and σ is the portion of the cone z=x2+y2−−−−−−√ between the planes z=4 and z=5 oriented with normal vectors pointi

ng upwards. Find the flux of the flow field F across σ
Mathematics
1 answer:
trapecia [35]2 years ago
4 0
There is no question for me to answer
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Amiraneli [1.4K]

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Stells [14]

Answer:

36

Step-by-step explanation:

3 x 3 x 4 =

9 x 4 =

36

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