F = xi+yj+2zk and σ is the portion of the cone z=x2+y2−−−−−−√ between the planes z=4 and z=5 oriented with normal vectors pointi
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Answer:
<h2>Area of the regular octagon is approximately 102ft²</h2>Step-by-step explanation:
Given the radius and length of a side of regular octagon as shown;
radius = 6ft and length of side = 4.6ft
Area of a regular octagon is expressed as where a is the length of one side. Given a = 4.6ft
Area =
Area of the regular octagon is approximately 102ft²