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2 years ago

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F = xi+yj+2zk and σ is the portion of the cone z=x2+y2−−−−−−√ between the planes z=4 and z=5 oriented with normal vectors pointi

ng upwards. Find the flux of the flow field F across σ

1 answer:

trapecia [35]2 years ago

4 0

There is no question for me to answer

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3 years ago

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Newton’s law of cooling states that the temperature of an object changes at a rate proportionalto the difference between the tem

Verizon [17]

Answer:

$\frac{dT}{dt} = -0.05\;min^{-1} (T-70\ºF)$

Step-by-step explanation:

Hi!

Lets call:

T = temprature of the object

T₀ = temperature of surroundings

t = time

The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:

$\frac{dT}{dt} = -k(T-T_0) \\$

In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:

$\frac{dT}{dt} = -0.05\;min^{-1} (T-70\ºF)$

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