Copper mass = 1.659
Copper moles = 1.659 / 64 = 0.0259
Sulfur mass = 2.08 - 1.659 = 0.421
Sulfur moles = 0.421 / 32 = 0.0131
Ratio Copper : Sulfur = 2 : 1
Empirical formula: Cu ₂ S
Name: Copper (I) sulfide
Answer:
142.82 g
Explanation:
The following data were obtained from the question:
Volume of water = 12 mL
Volume of water + gold = 19.4 mL
Density of gol= 19.3 g/cm³
Mass of gold =.?
Next, we shall determine the volume of the gold. This can be obtained as follow:
Volume of water = 12 mL
Volume of water + gold = 19.4 mL
Volume of gold =.?
Volume of gold = (Volume of water + gold) – (Volume of water)
Volume of gold = 19.4 – 12
Volume of gold = 7.4 mL
Finally, we shall determine the mass of the gold as follow:
Note: 1 mL is equivalent to 1 cm³
Volume of gold = 7.4 mL
Density of gol= 19.3 g/cm³ = 19.3 g/mL
Mass of gold =?
Density = mass /volume
19.3 = mass of gold /7.4
Cross multiply
Mass of gold = 19.3 × 7.4
Mass of gold = 142.82 g
Therefore, the mass of the gold pebble is 142.82 g
Answer:
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when Kc = [the concentration of products]^(no.of its mol in the balanced equation) / [the concentration of the reactants]^(no.of mol in the balanced equation)
∴ The equilibrium constant expression for this reaction is:
Kc= [H+]^2 * [So4-2] / [H2SO4]
