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xz_007 [3.2K]
3 years ago
6

A cart at rest accelerates to a speed of 30 meters per second over a 3.0 second time interval. What is the average velocity of t

he cart during these 3.0 seconds? P.4B
Physics
1 answer:
Zarrin [17]3 years ago
4 0

Answer:

15 m/s

Explanation:

Given data

Initial velocity= 0m/s----------since the cart was at rest

Final velocity = 30m/s

time= 30 seconds

Required

the average speed

We know that the sum of the initial and final velocity is divided by 2 to find the average velocity

average velocity= 0+30/2

average velocity= 30/2

average velocity= 15 m/s

Hence the average velocity is 15 m/s

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A rocket passes you at a speed of 0.85c, and you measure its length to be 35.0 m. What is its measured length when at rest?
viktelen [127]

Answer:

66.4 m

Explanation:

To solve the problem, we can use the length contraction formula, which states that the length observed in the reference frame moving with the object (the rocket) is given by

L=L_0 \sqrt{1-(\frac{v}{c})^2}

where

L_0 is the proper length (the length measured from an observer at rest)

v is the speed of the object (the rocket)

c is the speed of light

Here we know

v = 0.85c

L = 35.0 m

So we can re-arrange the equation to find the length of the rocket at rest:

L_0 = \frac{L}{\sqrt{1-(\frac{v}{c})^2}}=\frac{35.0}{\sqrt{1-(\frac{0.85c}{c})^2}}=66.4 m

8 0
4 years ago
Two electrons are initially at rest separated by a distance of 2nm. At time t=0, they start to move apart due to Coulombic repul
Gnom [1K]

Answer:

t=2.5\times 10^{-14}\ s

Explanation:

We know that charge on electron

q=1.6\times 10^{-19}\ C

r= 2 nm

We know that force between two charge given

F=K\dfrac{Q_1Q_2}{r^2}

Now by putting the value

F=9\times10^9\dfrac{1.6\times 10^{-19}\times 1.6\times 10^{-19}}{(2\times 10^{-9})^2}

F=5.67\times 10^{-11}\ N

We know that mass of electron

The mass of electron

m=9.1\times 10^{-31}\ kg

F= m a

a= Acceleration of electron

a= F/m

a=\dfrac{5.67\times 10^{-11}}{9.1\times 10^{-31}}\ m/s^2

a=6.2\times 10^{19} m/s^2

S=ut+\dfrac{1}{2}at^2

initial velocity given that zero ,u=0

20\times 10^{-9}=\dfrac{1}{2}\times 6.2\times 10^{19} t^2

t=\sqrt {\dfrac{40\times 10^{-9}}{6.2\times 10^{19}}}

t=2.5\times 10^{-14}\ s

3 0
4 years ago
If an astronaut throws an object in space, the object's speed will _____________. A) decrease. B) increase. C) remain constant.
GenaCL600 [577]

The object's speed will remain constant after the it leaves his hand.

So will HIS speed in the opposite direction.

7 0
3 years ago
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A dog has a weight of 700N find the mass of the dog
Stolb23 [73]
The specific answer for that will be 71.38 kg
8 0
4 years ago
The ancient Greek recommendation of rest in the treatment of abnormal behavior soon gave rise to ______. A. Trephining B. The as
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C. Is the correct answer
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