Answer:
The density of the box is 0.15 g/cm³
Explanation:
Given;
mass of the box, m = 15 g
dimension of the box, = 10 cm by 5 cm by 2 cm
Volume of the box, v = 10 cm x 5 cm x 2 cm = 100 cm³
The density of the box is given by;
Density = mass / volume
Density = 15 g / 100 cm³
Density = 0.15 g/cm³
Therefore, the density of the box is 0.15 g/cm³
Answer:
No, the net force on the skydiver is zero
Explanation:
According to Newton's Second Law, the net force on an object is equal to the product between the mass of the object and its acceleration:

where
F is the net force
m is the mass of the object
a is the acceleration
In this problem, the acceleration of the skydiver is zero:
a = 0
This implies that also the net force on the skydiver is zero, according to the previous equation:
F = 0
So, the net force on the skydiver is zero. This occurs because the air resistance, which points upward, exactly balances the force of gravity on the skydiver, acting downwards.
Nonononononononononononononononononono
Answer:
angular acceleration is -0.2063 rad/s²
Explanation:
Given data
mass m = 95.2 kg
radius r = 0.399 m
turning ω = 93 rpm
radial force N = 19.6 N
kinetic coefficient of friction μ = 0.2
to find out
angular acceleration
solution
we know frictional force that is = radial force × kinetic coefficient of friction
frictional force = 19.6 × 0.2
frictional force = 3.92 N
and
we know moment of inertia that is
γ = I ×α = frictional force × r
so
γ = 1/2 mr²α
α = -2f /mr
α = -2(3.92) /95.2 (0.399)
α = - 7.84 / 37.9848 = -0.2063
so angular acceleration is -0.2063 rad/s²
T(°C) = (T(°F) - 32) × 5/9
T(°F) = T(°C) × 9/5 + 32