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notsponge [240]
2 years ago
11

You toss a tennis ball straight upward. At the moment it leaves your hand it is at a height of 1.5 m above the ground, and it is

moving at a speed of 7.0 m/s.
(a) How much time does it take for the tennis ball to reach its maximum height? (s)

(b) What is the maximum height above the ground that the tennis ball reaches? (m)

(c) When the tennis ball is at a height of 2.4 m above the ground, what is its speed? (m/s)
Physics
1 answer:
ollegr [7]2 years ago
4 0

My answer was incorrect, please disregard.

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3 years ago
Calculate the power transfer when a pump moves 50kg of water through a vertical height of 8meters in 5seconds (take g =10meters
Vika [28.1K]

Hi there!

Recall the following relationships:

W = \Delta U = mg\Delta h\\\\P = \frac{W}{t}

W = Work (J)

U = Potential Energy (J)

m = mass (kg)

g = acceleration due to gravity (9.8 m/s²)

h = height (m)

t = time (s)

Begin by calculating the work:

W = 50(10)(8) = 4000 J

Now, divide by the time to solve for power:

P = \frac{4000}{5} = \boxed{800W}

**W is the unit for power (Watts).  Be careful not to get the two confused.

4 0
2 years ago
A rock is launched vertically upward by a slingshot. The elastic band of the slingshot accelerates the rock from rest to 40 m/s
eimsori [14]

Answer:

0.016 s

Explanation:

Initial velocity, u = 0

use the third equation of motion to find the acceleration of the rock.

2as=v^2-u^2\\a = \frac{40^2-0}{2\times0.1} =8000 m/s^2

Net displacement in the vertical direction would be zero. y = 0

Use second equation:

s=ut+\frac{1}{2}at^2\\0=0+\frac{1}{2}(8000)t^2\\t= 0.016 s

Thus, the rock will return to its initial release point in 0.016 s.

5 0
3 years ago
DIFFERENT PICTURE.... WHAT IS HAPPENING IN THIS PICTURES
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2. Energy is being removed to cause condensation.
8 0
2 years ago
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The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volu
photoshop1234 [79]

Answer:

\boxed{ V_{2}= 0.03189 m^3}

Explanation:

According to Charles Law

=> \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

Where V_{1} = 0.0279 m³, T_{1} = 280 K and T_{2} = 320 K

=> \frac{0.0279}{280} = \frac{V_{2}}{320}

=> V_{2} = 0.03189 m³

7 0
3 years ago
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