Answer:
Given
acceleration (a) =1.5ms2
Force(F) =2100N
R. t. c mass (m) =?
Form
F=ma(divided by m both sides)
m=F/a
m=2100/105
m=1400kg
mass of car =1400kg
If the surface is rough then the average force needed to move the wooden block will be more as the friction between the surfaces will be more.
Hence, the least force will be required on the smoothest surface and the greatest force will be required for the roughest surface.
a) Hence, the order will be: B > D > A > C
b) When the surface is glued then the force of friction will increase. Hence, it will require more force to move the wooden block on the surface. Hence, the more required will be more than 105 N.
100 ml
100 ml of the stock solution is required to prepare the order.
We know that C1V1 = C2V2
where C1= 2%
V1 = 500ml
C2= 10%
V2 = ?
V2 = C1V1 / C2
= 500 * 2% / 10%
=100
V2 = 100 ml
<h3>What is meant by stock solution?</h3>
- A stock solution is a sizable amount of a typical reagent in a standardized concentration, like sodium hydroxide or hydrochloric acid.
- This phrase is frequently used in analytical chemistry while doing operations like titrations where it's crucial to employ precise solution concentrations.
<h3>What distinguishes a standard solution from a stock solution?</h3>
- The main distinction between stock solution and standard solution is that the former is a highly concentrated solution while the later is a solution whose concentration is precisely known.
- Because standard solutions frequently arrive as stock solutions, the phrases "stock solution" and "standard solution" are connected.
To learn more about stock solution preparation visit:
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Answer:
150m
Explanation:
The relation of speed/time and distance/time is a derivative/integral one, as in speed is the derivative of distance (the faster you go, the faster the distance changes, duh!).
So we need to compute the integral of speed over time from 0.0s to 5.0s.
The easiest way here is to compute the area under the line (it's going to be faster than computing the acceleration and using a formula of distance based on acceleration).
The area under the line is a trapezoid with "height" 5s, and the bases 10m/s and 50m/s. Using the trapezoid area formula of h*(a + b)/2
distance = 5s * (10m/s + 50m/s) / 2 = 5s * 60m/s / 2 = 5s * 30m/s = 150m
Alternatively, we can use the acceleration formula:
a = (50m/s - 10m/s)/5s = 40m/s / 5s = 8m/s^2
distance = v0 * t + a * t^2 / 2 = 10m/s * 5s + 8m/s^2 * (5s)^2 / 2 = 50m + 8m * 25 / 2 = 50m + 100m = 150m.
Because their is nothing at the geographical poles that attracts the magnet
