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Kay [80]
3 years ago
8

Find a rational number halfway in between the two numbers. 7/9 and 3/4​

Mathematics
1 answer:
AlekseyPX3 years ago
7 0

Answer: 55/126

Step-by-step explanation:

For this equation, the easiest way to solve is to change the denominators, or bottom halves, of both fractions to be the same thing. The easiest way to do this is to multiply themselves with a “funny form” of one. A funny form of one is just a way of representing “1” with numbers that aren’t 1. “2/2” is a funny form of one. log(x)/log(x) is a funny form of one, etc..

(3/7)x(9/9)=27/63

(4/9)x(7/7)=28/63

These fractions are very close. If you are willing to settle for an unsimplified fraction, the answer here would be 27.5/63. If you aren’t willing to settle for the unsimplified form, we can multiply both fractions by a funny form of one again, most easily 2/2, and find the median of the two fractions.

(27/63)x(2/2)=54/126

(28/63)x(2/2)=56/126

The median of these two fractions is 55/126.

55/126 is exactly halfway between 3/7 and 4/9.

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Which steps show how to use the distributive property to evaluate 9.32?
MAVERICK [17]

Answer:

D

Step-by-step explanation:

3 0
2 years ago
The number of ways 8 cars can be lined up at a toll booth would be computed from
stepladder [879]

Answer: c. 8!

Step-by-step explanation:

We know , that if we line up n things , then the total number of ways to arrange n things in a line is given by :-

n! ( in words :- n factorial)

Therefore , the number of ways 8 cars can be lined up at a toll booth would be 8! .

Hence, the correct answer is c. 8! .

Alternatively , we also use multiplicative principle,

If we line up 8 cars , first we fix one car , then the number of choices for the next place will be 7 , after that we fix second car ,then the number of choices for the next place will be 6 , and so on..

So , the total number of ways to line up 8 cars = 8 x 7 x 6 x 5 x 4 x 3 x 2 x1 = 8!

Hence, the correct answer is c. 8! .

5 0
3 years ago
Graph the line with slope −2 passing through the point , 5−1.
Allisa [31]

<u>Answer:</u>

<u>y+1=-2(x-5)</u> - Point Slope Form

<u>y=-2x+9</u> - Slope Intercept Form

<u></u>

Step-by-step explanation:

We will be using point-slope formula, as attached in a picture below.

1) Plug in the slope -2 as "m" in point slope form, along with the two points, (5, -1)

<u>y+1=-2(x-5)</u>

2) Next, if you want to put the line into slope-intercept form, you will need to distribute -2 to x and -5:

y+1=-2x+10

3) Now, subtract 1 from both sides:

<u>y=-2x+9</u>

6 0
3 years ago
Find the distance between the two points in simplest radical form.<br> (1, -7) and (7,0)
denis23 [38]

Answer:

The <u>distance</u> <em>between</em> the two given points is equal to √85.

Step-by-step explanation:

Let's recall what the distance formula is:

\displaystyle \huge\math\boxed{d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2} }

We are defined our two points as:

  • (x₁, y₁) → (1, -7)
  • (x₂, y₂) → (7, 0)

We can rewrite this into our different "variables":

  • x₁ = 1
  • y₁ = -7
  • x₂ = 7
  • y₂ = 0

Now given our distance formula and our variables, we can find the distance between the two points:

\displaystyle\huge\begin{aligned}d & = \sqrt{(1 - 7)^2 + (7 - 0)^2} \\& = \sqrt{(-6)^2 + (7)^2} \\& = \sqrt{36 + 49} \\& = \math\boxed{\sqrt{85}} \\\end{aligned}

∴ since the radical is already in its simplest form, our distance between the two points is equal to √85.

Hope this helps!

5 0
2 years ago
Read 2 more answers
Animals were trapped in a city and later released into the wild. A random sample of the data is provided in the table below.
Fynjy0 [20]

Answer:

c

1,400

Step-by-step explanation:

We take the sample proportion of skunks and estimate for the entire population.

Sample:

140 skunks out of 230 + 140 + 120 = 490 animals.

140/490 = 0.28571428571

If a random sample of 5,000 animals are trapped in the city, how many skunks would be estimated to be included?

0.28571428571 out of 5000. So

0.28571428571*5000 = 1429

Close to 1400, which means that the answer is given by option C.

6 0
2 years ago
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