Answer:
a) t=24s
b) number of oscillations= 11
Explanation:
In case of a damped simple harmonic oscillator the equation of motion is
m(d²x/dt²)+b(dx/dt)+kx=0
Therefore on solving the above differential equation we get,
x(t)=A₀
where A(t)=A₀
A₀ is the amplitude at t=0 and
is the angular frequency of damped SHM, which is given by,
Now coming to the problem,
Given: m=1.2 kg
k=9.8 N/m
b=210 g/s= 0.21 kg/s
A₀=13 cm
a) A(t)=A₀/8
⇒A₀ =A₀/8
⇒
applying logarithm on both sides
⇒
⇒
substituting the values
b)
, where is time period of damped SHM
⇒
let be number of oscillations made
then,
⇒
Answer:
V
Explanation:
The volt (symbol of the unit of volts, V ) is the SI - unit for electric potential and electric voltage (potential difference).
Answer:
= 38.89 m/s
Explanation:
speed of first car (u) = 80 km/h = 22.22 m/s
time (t) = 30 s
distance (d) = 500 m
find the speed of second car (v)
let the speed of the second car be represented as 'v'
We can get the speed of the second car from the formula net speed = distance between cars / time interval
where
- distance between cars = 500 m
- time interval = 30 s
- net speed = v-22.22 (since both cars move in the same direction)
- substituting the above into the formula we have
v-22.22 = 500 / 30
v = 500/30 + 22.22
v = 38.89 m/s